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KiRa [710]
2 years ago
15

Charlene is knitting a baby blanket. She wants its width, w, to be at least half its length, l. She estimates that she has enoug

h yarn to put fringe around the blanket, as long as the perimeter of the blanket is no more than 180 inches. The system of inequalities shown represents the width of the blanket in inches, w, and the length in inches, l.
w ≥ 0.5l

2l + 2w ≤ 180

What is the maximum length possible for her blanket?

a 30 inches
b 45 inches
c 60 inches
d 90 inches
Mathematics
2 answers:
jolli1 [7]2 years ago
7 0
I believe the answer is C - 60 inches. 60 x 2 = 120, which is both lengths, and since he width is half the length, then 30 x 2 = 60. So 130 (length) + 60 (width) = 180. So 60 inches would be the maximum length for both sides.
kaheart [24]2 years ago
5 0

Answer:

C.)60 inches

Step-by-step explanation: keep it simple



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The bar graph shows the number of school days Jalen had homework and did not have homework during the first six months of
Oksanka [162]

Given:

<u>In July:</u>

Number of days he has done the homework = 6

Number of days he has not done the homework = 4

<u>In August:</u>

Number of days he has done the homework = 16

Number of days he has not done the homework = 7

<u>In September:</u>

Number of days he has done the homework = 14

Number of days he has not done the homework = 4

<u>In October:</u>

Number of days he has done the homework = 14

Number of days he has not done the homework = 8

<u>In November:</u>

Number of days he has done the homework = 16

Number of days he has not done the homework = 4

<u>In December:</u>

Number of days he has done the homework = 5

Number of days he has not done the homework = 10

To find the months in which the difference between the number of days with homework and with no homework greater than 6.

Now,

<u>In July,</u>

The difference between the number of days with homework and with no homework = 6-4 = 2

<u>In August,</u>

The difference between the number of days with homework and with no homework = 16-7 = 9

<u>In September,</u>

The difference between the number of days with homework and with no homework = 14-4 = 10

<u>In October,</u>

The difference between the number of days with homework and with no homework = 14-8 = 6

<u>In November,</u>

The difference between the number of days with homework and with no homework = 16-4 = 12

<u>In December,</u>

The difference between the number of days with homework and with no homework = 10-5 = 5

Hence,

In 3 months the difference between the number of days with homework and with no homework greater than 6 and these are: August, September, November.

4 0
3 years ago
A standard six-sided die is rolled twice and the top faces are observed. What is the probability that the sum of the numbers on
melisa1 [442]

<u>Answer: </u>

A standard six-sided die is rolled twice and the top faces are observed and the probability that the sum of the numbers on the top faces is 10 is \frac{1}{12}

<u>Solution: </u>

The sample space of two dice outcomes is given as follows:

{(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)

(2, 1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3, 1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4, 1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5, 1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6, 1) (6,2) (6,3) (6,4) (6,5) (6,6) }

Total number of events n(s) = 36

Expected Outcomes = {(4, 6), (5, 5), (6, 4)}

Number of favorable outcomes n(E) = 3

Probability (sum of numbers on the top faces is 10) = \frac{n(E)}{n(s)} = \frac{3}{36} = \frac{1}{12}

Therefore the probability that the sum of the numbers on the top faces is 10 is \frac{1}{12}

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3 years ago
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Ummmm could u ask a question because this makes no sense are you adding subtracting what?
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2 years ago
Round 2.8125 to the nearest hundred please help
ZanzabumX [31]

Answer:

2.81

Step-by-step explanation:

3 0
3 years ago
Dentify the location of the values square root of 10, square root of 13, and twenty two ninths on the number line.
Goshia [24]

A <em>number line</em> is a <u>system</u> that shows the location of all <em>directed numbers </em>on a <u>straight</u> <u>line</u>. All <em>numbers</em> can be plotted on a <em>number line</em>. Thus the required answer to the given question is; Option A. Point A is <em>twenty-two</em> <em>ninths</em>, point B is <em>square root</em> of 10, and point C is <em>square root</em> of 13.

A <u>line</u> on which the <em>locations</em> of all <em>directed number</em>s can be shown is termed a <u>number line</u>. It has <u>two</u> extreme ends ranging from -∞ to +∞. Note that all <em>numbers</em> can be plotted on a <em>number line</em>. So that the <u>position</u> of any given <em>number</em> can be shown on the <u>line</u>.

In the given question, we have:

i. square root of 10 = \sqrt{10}

                               = 3.2

ii. square root of 13 = \sqrt{13}

                                = 3.6

iii. twenty-two ninths = \frac{22}{9}

                                  = 2.4

But it has been given that;

Number line with points plotted at; <em>two</em> and <em>four-tenths</em> labeled point<u> A,</u> <em>three</em> and <em>two-tenths</em> labeled point <u>B</u>, and <em>three</em> and <em>six-tenths</em> labeled Point <u>C.</u>

Therefore,

Point A is <em>twenty-two ninths</em>, point B is <u>square</u> <u>root </u>of 10, and point C is <em>square root</em> of 13.

Thus the correct <u>option</u> is A.

For more clarifications on number line visit: brainly.com/question/22567573

#SPJ1

6 0
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