Solve log28 + log232. A. 2 B. log240 C. 2 log210 D. 8
2 answers:
You might be interested in
This is the answer to your question
Answer:
There is a 12.13% probability that the person actually does have cancer.
Step-by-step explanation:
We have these following probabilities.
A 0.9% probability of a person having cancer
A 99.1% probability of a person not having cancer.
If a person has cancer, she has a 91% probability of being diagnosticated.
If a person does not have cancer, she has a 6% probability of being diagnosticated.
The question can be formulated as the following problem:
What is the probability of B happening, knowing that A has happened.
It can be calculated by the following formula
Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.
In this problem we have the following question
What is the probability that the person has cancer, given that she was diagnosticated?
So
P(B) is the probability of the person having cancer, so
P(A/B) is the probability that the person being diagnosticated, given that she has cancer. So
P(A) is the probability of the person being diagnosticated. If she has cancer, there is a 91% probability that she was diagnosticard. There is also a 6% probability of a person without cancer being diagnosticated. So
What is the probability that the person actually does have cancer?
There is a 12.13% probability that the person actually does have cancer.
Your formula for this is 
and 
. Get everything on one side of the equals sign, set it equal to 0 and factor. When you do this you get (x-3)(x+27). The Zero Product Property rule tells us that either x-3 = 0 or x+27 = 0 and that x = 3 and -27. The only thing in math that will NEVER be negative besides time is distance/length, therefore, x cannot be 27 and has to be 3.