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Veronika [31]
4 years ago
10

The Solubility Product Constant for calcium bromide is > 1. If calcium bromide is dissolved in water you can say that the equ

ilibrium concentrations of calcium and bromide ions are: ... ...A. High ...B. Moderate ...C. Low The solubility of calcium bromide in water is: ... ...A. High ...B. Moderate ...C. Low
Chemistry
1 answer:
DiKsa [7]4 years ago
7 0

Answer: (1). If calcium bromide is dissolved in water you can say that the equilibrium concentrations of calcium and bromide ions are high.

(2). The solubility of calcium bromide in water is high.

Explanation:

We know that for a reaction its solubility product is equal to the product of concentration of ions present.

For example, CaBr_{2} \rightarrow Ca^{2+} + 2Br^{-}

      K_{sp} = [Ca^{2+}][Br^{-}]^{2}

As it is given that for this reaction K_{sp} > 1. Hence, the product of concentration of both these ions will be greater than 1 which means that products are favored.

Therefore, equilibrium concentrations of calcium and bromide ions are high.

Also, more is the number of these ions formed more will be the solubility of the compound (CaBr_{2}).

As a result, the solubility of calcium bromide in water is high.

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What does the mass number of an atom represent?.
mamaluj [8]

Answer:

the sum of the numbers of protons and neutrons present in the nucleus of an atom.

8 0
2 years ago
A blacksmith heated an iron bar to 1445 °C. The blacksmith then tempered the metal by dropping it into 42,800 mL of
Wittaler [7]

Answer:

6626 g

Explanation:

Given that:

Density of water = 1.00 g/ml, volume of water = 42800 ml.

Since density = mass/ volume

mass of water = volume of water * density of water = 42800 ml * 1 g/ml = 42800 g

Initial temperature of water = 22°C and final temperature of water = 45°C.

specific heat capacity for water = 4.184 J/g°C

ΔT water = 45 - 22 = 23°C

For iron:

mass = m,  

specific heat capacity for iron  = 0.444 J/g°C

Initial temperature of iron = 1445°C and final temperature of water = 45°C.

ΔT iron = 45 - 1445 = -1400°C

Quantity of heat (Q) to raised the temperature of a body is given as:

Q = mCΔT

The quantity of heat required to raise the temperature of water is equal to the temperature loss by the iron.

Q water (gain) + Q iron (loss) = 0

Q water = - Q iron

42800 g ×  4.184 J/g°C × 23°C = -m × 0.444 J/g°C × -1400°C

m = 4118729.6/621.6

m = 6626 g

8 0
3 years ago
2. Which state of matter will take both the volume
Vikentia [17]

Answer:

The answer would be C) a liquid.

Explanation:

If you were to pour a glass of water into a rectangular container, the water would fill up the container and be in the same shape as the container. That is becuase water flows and it doesn't harden up or take its own shape until it's frozen. The molecules are not tightly secure to each other so they are able to move freely.

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3 years ago
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kolezko [41]

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I would say there would be 5-10% in a city, and maybe 10-20% in the country. It mainly varies depending on how big the city is, how many people/districts there are, and the size of the country, which makes it hard to give a certain percent of shops, as there may be small businesses included as well or new shops being built.

Hope this helps! This was pretty confusing for me as well so i hope the answer is alright (×﹏×)

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2 years ago
Which type of rock can melt to become magma?
KIM [24]
The answer is an igneous rock.

Hope this helps!!
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3 years ago
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