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3 years ago

A square has a side length of 18 centimeters what is it’s perimeter

Mathematics

1 answer:

NARA [144]3 years ago

3 0

The perimeter is 72 because all sides on a square are the same measurements so you just have to do 18 times 4 to get 72

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Use properties to find the sum or product. <br> 93+(68+7)

erma4kov [3.2K]

$93+(68+7)=93+68+7\\use\ commutative\ property: a+b=b+a\\\\=93+7+68\\use\ associative\ property:a+(b+c)=(a+b)+c\\\\=(93+7)+68=100+68=\huge\boxed{168}$

6 0

3 years ago

Find a linear second-order differential equation f(x, y, y', y'') = 0 for which y = c1x + c2x3 is a two-parameter family of solu

Alisiya [41]

Let $y=C_1x+C_2x^3=C_1y_1+C_2y_2$ . Then $y_1$ and $y_2$ are two fundamental, linearly independent solution that satisfy

$f(x,y_1,{y_1}',{y_1}'')=0$
$f(x,y_2,{y_2}',{y_2}'')=0$

Note that ${y_1}'=1$ , so that $x{y_1}'-y_1=0$ . Adding $y''$ doesn't change this, since ${y_1}''=0$ .

So if we suppose

$f(x,y,y',y'')=y''+xy'-y=0$

then substituting $y=y_2$ would give

$6x+x(3x^2)-x^3=6x+2x^3\neq0$

To make sure everything cancels out, multiply the second degree term by $-\dfrac{x^2}3$ , so that

$f(x,y,y',y'')=-\dfrac{x^2}3y''+xy'-y$

Then if $y=y_1+y_2$ , we get

$-\dfrac{x^2}3(0+6x)+x(1+3x^2)-(x+x^3)=-2x^3+x+3x^3-x-x^3=0$

as desired. So one possible ODE would be

$-\dfrac{x^2}3y''+xy'-y=0\iff x^2y''-3xy'+3y=0$

(See "Euler-Cauchy equation" for more info)

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3 years ago

Lee records the height of players on a basketball team and calculates the mean absolute deviation of the set of data.

ladessa [460]

Answer:

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3 years ago

Percent of discount is 25% and the sale price is 40$ what is the original amount?

Crank

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3 years ago

Find the value of x (5x+4)=(8x-71)

sesenic [268]

Answer:

5x +4 =8x - 71

-3x +4 = -71

-3x= -75

x= 25

3 0

2 years ago

Read 2 more answers