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Irina18 [472]
3 years ago
10

I think of a number, then divide by 8, then

Mathematics
2 answers:
kogti [31]3 years ago
8 0

Answer:

14

Step-by-step explanation:

plz tell me if im right

enot [183]3 years ago
7 0

Answer:

I'm not a math expert but I was able to figure this out Somehow .  the answer is 896.

Step-by-step explanation:

Sounds crazy but trust me the answer is 896. I did the math on a calculator, and im looking through the history.

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Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial in s
Lerok [7]

Answer:

Q1 - D. f(x) = x^4-9x^2-50x-150

Q13 - A. ±1, ±2, ±3, ±4, ±6, ±8, ±12, ±24.

Q14 - A. 7x+6+4x^{2}

Step-by-step explanation:

Question 1:

We know that rational roots always occurs in pairs. So, the zeros of the function will be 5, -3, -1+3i, -1-3i

So, the factored form is (x-5)(x+3)(x+1-3i)(x+1+3i)=0

i.e. (x^2-2x-15)(x+1-3i)(x+1+3i)=0

i.e. (x^3-x^2-3ix^2-17x+6ix-15+45i)(x+1+3i)=0

i.e. x^4-9x^2-50x-150=0

Hence, the polynomial function is f(x)=x^4-9x^2-50x-150.

Question 13:  

Rational Zeros Theorem states that 'If p(x) is a polynomial with integer coefficients and if \frac{p}{q} is a zero of p(x) = 0. Then, p is a factor of the constant term of p(x) and q is a factor of the leading coefficient of p(x)'.

Let, \frac{p}{q} is a zero of x^3-7x^2+9x-24=0. Then, p is a factor of -24 and q is a factor of 1.

Thus, possible values of p = ±1, ±2, ±3, ±4, ±6, ±8, ±12, ±24 and q = ±1

This gives, possible values of \frac{p}{q} are ±1, ±2, ±3, ±4, ±6, ±8, ±12, ±24.

Question 14:

We have, f(x) = 7x + 6 and g(x) = 4x^{2}

Then, (f+g)(x) = f(x) + g(x) =  7x + 6 + 4x^{2}

So, (f+g)(x) = 7x+6+4x^{2}

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