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frozen [14]
2 years ago
15

Is 8/9 a terminating decimal or a repeating decimal

Mathematics
2 answers:
satela [25.4K]2 years ago
4 0

Answer:

it's is a repeating decimal

Anni [7]2 years ago
4 0

Answer:

8/9 = 0.88888...

This decimal never stops and keeps on repeating, so it is a repeating decimal.

Let me know if this helps!

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A construction company purchased some equipment costing $300,000. The value of the equipment depreciates
goldfiish [28.3K]

Answer:

11.9\ years  

Step-by-step explanation:

we know that

The  formula to calculate the depreciated value  is equal to  

V=P(1-r)^{x}  

where  

V is the depreciated value  

P is the original value  

r is the rate of depreciation  in decimal  

x  is Number of Time Periods  

in this problem we have  

P=\$300,000\\r=14\%=14/100=0.14\\V=\$50,000

substitute the values and solve for x

50,000=300,000(1-0.14)^{x}  

(50,000/300,000)=(0.86)^{x}  

(5/30)=(0.86)^{x}  

Apply log both sides

log(5/30)=(x)log(0.86)  

x=log(5/30)/log(0.86)  

x=11.9\ years  

4 0
3 years ago
Read 2 more answers
Could someone help me on question 1<br><br>thx
Ghella [55]
The answer is A!!! Hope that helped :)
4 0
2 years ago
Three baseball players are playing catch. Philip is directly south of Barbara and directly west of Savannah. Philip and Savannah
Kitty [74]
Philip and Barbara are 8 meters apart because 5+3=8 so it will make 8 meters
4 0
2 years ago
Triphasil-28 birth control tablets are taken sequentially, 1 tablet per day for 28 days, with the tablets containing the followi
bazaltina [42]

Answer:

1.925mg of levonorgestrel and 0.68mg of ethinyl estradiol are taken during the 28-day period.

Step-by-step explanation:

The total milligrams of levonorgestrel is:

L = L_{1} + L_{2} + L_{3}

In which L_{1}, L_{2} and L_{3} are the number of miligrams of levonorgestrel taken in each phase.

The total milligrams of ethinyl estradiol is:

E = E_{1} + E_{2} + E_{3}

In which E_{1},E_{2} and E_{3} are the number of miligrams of ethinyl estradiol taken in each phase.

We can solve this by phase.

Phase 1: 6 tablets, each containing 0.050 mg of levonorgestrel and 0.030 mg ethinyl estradiol

In this phase,

6*0.050mg = 0.30mg of levonorgestrel and 6*0.030mg = 0.18mg of ethinyl estradiol are taken.

So L_{1} = 0.30 and E_{1} = 0.18

Phase 2: 5 tablets, each containing 0.075 mg of levonorgestrel and 0.040 mg ethinyl estradiol

In this phase,

5*0.075mg = 0.375mg of levonorgestrel and 5*0.040mg = 0.20mg of ethinyl estradiol are taken.

So L_{2} = 0.375 and E_{2} = 0.20

Phase 3: 10 tablets, each containing 0.125 mg of levonorgestrel and 0.030 mg ethinyl estradiol

In this phase,

10*0.125mg = 1.25mg of levonorgestrel and 10*0.030mg = 0.30mg of ethinyl estradiol are taken.

So L_{3} = 1.25 and E_{3} = 0.30

The total milligrams of levonorgestrel is:

L = L_{1} + L_{2} + L_{3} = 0.30 + 0.375 + 1.25 = 1.925

The total milligrams of ethinyl estradiol is:

E = E_{1} + E_{2} + E_{3} = 0.18 + 0.20 + 0.30 = 0.68

1.925mg of levonorgestrel and 0.68mg of ethinyl estradiol are taken during the 28-day period.

6 0
2 years ago
What equation can I make out of this problem
Ghella [55]
5(4)+5x=60
x=8
x= number of pies the club made
7 0
3 years ago
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