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jolli1 [7]
3 years ago
6

Can someone help me with this question, again?

Mathematics
1 answer:
givi [52]3 years ago
7 0
A. 4*1 - 3*2 = 4 - 6 = -2 (X
B. 4*4 - 3*2 = 16 - 6 = 10 (O
C. 4*7 - 3*6 = 28 - 18 = 10 (O
D. 4*4 - 3*(-3) = 16 + 9 = 25 (X

so the answers are B and C
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Which compound inequalities have the solution set represented by the given graph? Check all that apply
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We check with each options

'Or' represents the intersection of two graphs

'And' represents two separate graphs'

We have two separate shaded part in the given graph

So we ignore the options that has 'and' in between

LEts check first  and second option

\frac{x}{2}=13

Simplify the first part and second part

multiply both sides by 2 .

x < 2  or  4x - 2 > = 26

solve 4x-2 > = 26

add 2 on both sides and then divide both sides by 4

4x >= 28

x >= 7

So solution is x<2 or x>=7 . that is the graph on number line

Lets check with second option

3x-3<3  or  2x+8>=22

add 3 on both sides

3x < 6

divide both sides by 3

so x< 2

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subtract 8 on both sides

2x >= 30

divide both sides by 2

x >= 15

x<2  or x>=15 that does not satisfies the graph

So option A is correct



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3 years ago
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2 years ago
−2/3a+1/8−1/6a−3/4 PLEASE HELP
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Answer:

Evaluate:

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