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3 years ago

Find the area of the shaded region in the polygon below.

Mathematics

2 answers:

mezya [45]3 years ago

8 0

Answer:

Step-by-step explanation:

I multiply 3 and 7 that give 35

Goryan [66]3 years ago

8 0

Answer:

Step-by-step explanation:

The area of a pentagon given the radius is

Area = (5/2)r^2 * sin(72º)

r = 7

Area = (5/2)*7^2 * sin(72)

Area = 122.5 * 0.95106

Area = 116.5

=============

r = 5

Area = (5/2) * 5^2 * sin(72)

Area = 59.4

Area of the shaded area = 116.5 - 59.4

Area of the shaded area = 57.1

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Harold, the handyman, builds two similar sheds for a farm. The smaller shed is 6 feet tall and weighs 500 pounds. If it takes th

Akimi4 [234]

Answer:

18 ft

1500 pounds

Step-by-step explanation:

6 x 3 = 1 8

500 x 3 = 1500

7 0

3 years ago

The table below shows the numbers of tickets sold at a movie theater on Friday.

kondor19780726 [428]

Answer:

Number of Adult's tickets sold on Saturday = 3,356

Number of Children's tickets sold on Saturday = 2, 928

Total number of tickets sold over these two days is 8,938.

Step-by-step explanation:

Here, the number of tickets sold on FRIDAY:

Adult Ticket sold = 1,678

Children's Tickets sold = 976

So, the total number of tickets sold on Friday

= Sum of ( Adult + Children's ) tickets = 1,678 + 976 = 2,654 .... (1)

The number of tickets sold on SATURDAY:

Adult Ticket sold = 2 times the number of adult tickets sold on Friday

= 1,678 x 2 = 3,356

Children's Tickets sold = 3 times the number of children's tickets sold on Friday.

= 976 x 3 = 2, 928

So, the total number of tickets sold on Saturday

= Sum of ( Adult + Children's ) tickets = 3,356 + 2,928 = 6, 284 .... (2)

Now, the total number of tickets booked in these two days :

Sum of tickets booked on (Friday + Saturday)

= 2,654 + 6, 284 = 8,938

Hence, total number of tickets sold over these two days is 8,938.

6 0

4 years ago

May I please receive help???? <br> Please

zheka24 [161]

Answer:

43°

Step-by-step explanation:

<h2><u>Equation:</u></h2>

<u />

m∠ABD = m∠1 + m∠2

Substitute:

68° = m∠1 + (m∠1 + 18°)

<h2><u>Solve:</u></h2>

68° = m∠1 + (m∠1 + 18°)

68° = 2(m∠1) + 18°

50° = 2(m∠1)

25 = m∠1

<h2><u>Solution:</u></h2>

<u />

Know that we know that m∠1 is, we can add 18* to find m∠2

25° + 18° = 43°

-Chetan K

7 0

3 years ago

Twice the quotient of b and 24

Blizzard [7]

Equation: B/24 · 2. I hope that helps!

7 0

3 years ago

The area of a rectangle is 33 ft^2, and the length of the rectangle is 5 ft less than double the width. Find the dimensions of t

dimaraw [331]

Answer:

Length = 6

Width = 5.5

Step-by-step explanation:

Let's use the variable x to represent the width:

x = width

The question says that the length of the rectangle is "5 ft less than double the width". This length can be represented like this:

2x - 5 = length

To find the area of a rectangle, you multiply the width and length, so we are going to write an equation where we multiply the width and length and set it equal to 33 ft^2, which is the area:

(x)(2x - 5) = 33

Now use basic algebra to solve for x:

2x^2 - 5x = 33

2x^2 - 5x - 33 = 0

2x^2 + 6x - 11x - 33 = 0

(2x^2 + 6x) + (-11x - 33) = 0

2x(x + 3) - 11(x + 3) = 0

(2x - 11) (x + 3) = 0

x = 11/2, -3

x either equals 11/2 or -3. However, remember that x represents the width, and you can't have a negative number for a width, so x = 11/2 or 5.5.

Now plug in 5.5 to the length expression and simplify:

2(5.5) - 5

11 - 5 = 6

The length is 6 and the width is 5.5.

Hope this helps (●'◡'●)

7 0

3 years ago