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Tanzania [10]
3 years ago
8

Help asap will give brainliest

Mathematics
1 answer:
Arada [10]3 years ago
3 0
I use an app called Socratic also it works very well!!
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Find the height of the giraffe in the diagram below​
saveliy_v [14]

the giraffe is 18 feet tall.

3 0
3 years ago
Read 2 more answers
How many yards<br> carpeting is needed to cover a 60 feet length room and 40 feet width ​
Bad White [126]

Answer:

266 \frac{2}{3} yards

Step-by-step explanation:

1. Approach

First, convert the dimensions of the room from feet to yards. Remember, the conversion rate between feet and yards is, 3feet=1yard. Next, find the area of the room by multiplying the length by the width.

2. Convert the unit of measurement

The measurement unit is given in feet, one must convert it into yards. The conversion rate between yards and feet is, 3feet=1yard.

60feet=20yards\\\\40feet=13\frac{1}{3}yards

3. Find the area of the room

Now multiply the length by the width to find the area of the room.

20yards*13\frac{1}{3}yrads\\\\= 20 * \frac{40}{3}\\\\=\frac{800}{3}\\\\= 266\frac{2}{3}_{.}yards^{2}

5 0
3 years ago
Given the lengths of two sides of a triangle, find the range for the length of the third side. (Range means find between which t
Sidana [21]
<h3>Answer:  5 < x < 21</h3>

Explanation:

Let x be the length of the third side. We can't find the exact value of x, as we don't have enough info, but we can find possible values for x.

The lower boundary for x is 13-8 = 5. It must be larger than this value.

At the same time, x must be smaller than 13+8 = 21 as well.

So x > 5 and x < 21 becomes 5 < x < 21

In short, x is between 5 and 21. It cannot equal either endpoint.

3 0
3 years ago
How do you write 5 out of 6 in a fraction. Show how you got the answer.
antiseptic1488 [7]

Answer:

5/6

Step-by-step explanation:

bro ok this it ok okik

6 0
3 years ago
Read 2 more answers
Polynomial function in standard form with zeros 5,-4,1
Oksanka [162]

Answer:

\boxed{\sf \ \ \  x^3-2x^2-19x+20 \ \ \  }

Step-by-step explanation:

hello,

by definition we can write

(x-5)(x+4)(x-1)

as 5,-4,1 are the zeroes

now we have to write it in the standard form, let's do it

(x-5)(x+4)(x-1)=(x^2+4x-5x-20)(x-1)\\=(x^2-x-20)(x-1)=x^3-x^2-20x-x^2+x+20\\=x^3-2x^2-19x+20

hope this helps

5 0
3 years ago
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