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3 years ago

HELP ME PLEASE!!!!!!!

Mathematics

2 answers:

Diano4ka-milaya [45]3 years ago

5 0

Ill take a guess of... idk. the second or the third one.

aksik [14]3 years ago

3 0

The answer to this problem is 8x^8

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Gage's math teacher entered the seventh-grade student in a math competition. There was an enrollment fee of $30 and also $11 cha

Amanda [17]

Answer:

110 test

Step-by-step explanation:

Let

x ----> the number of packet of 10 test

y ----> the total cost

we know that

The number of packet of 10 test purchase multiplied by $11 plus the enrollment fee of $30 must be equal to $151

The linear equation that represent this scenario is

$y=11x+30$

we have

$y=\$151$

substitute

$151=11x+30$

Solve for x

subtract 30 both sides

$11x=151-30$

$11x=121$

Divide by 11 both sides

$x=11$

The number of packets purchase was 11

To find out the number of test, multiply the number of packets by 10

$11(10)=110\ test$

4 0

3 years ago

Someone please help thanks!<3

love history [14]

Answer:

y = -5x + 4/3

Step-by-step explanation:

m is the slope and b is the y intercept. m= -5 so -5 is the slope and b= 4/3 so 4/3 is the y intercept.

6 0

2 years ago

Ivan is painting 3 walls in his living room. Each wall measures 9 3/4 feet tall by 14 1/4 feet wide. Ivan needs to estimate the

Alenkinab [10]

Answer:

The estimated area is $416\frac{13}{16}\ ft^{2}$

Step-by-step explanation:

we know that

To estimate the area that Ivan will paint , calculate the area of one wall and then multiply by 3

step 1

Convert the dimensions to an improper fractions

$9\frac{3}{4}\ ft=\frac{9*4+3}{4}=\frac{39}{4}\ ft$

$14\frac{1}{4}\ ft=\frac{14*4+1}{4}=\frac{57}{4}\ ft$

step 2

Find the area of one wall

$(\frac{39}{4})*(\frac{57}{4})=\frac{2,223}{16}\ ft^{2}$

step 3

Multiply the area of one wall by 3

$(3)*\frac{2,223}{16}=\frac{6,669}{16}\ ft^{2}$

step 4

Convert to mixed number

$\frac{6,669}{16}=\frac{6,656}{16}+\frac{13}{16}=416\frac{13}{16}\ ft^{2}$

4 0

3 years ago

HELP URGENT BRAINLIEST

nadya68 [22]

Given:

LMN is an equilateral triangle.

LM = LN = MN = 12 cm

To find:

The height of the triangle h.

Solution:

In a right angle triangle,

$\sin \theta=\dfrac{Opposite}{Hypotenuse}$

$\sin (60^\circ)=\dfrac{h}{12}$

$\dfrac{\sqrt{3}}{2}=\dfrac{h}{12}$

Multiply both sides by 12.

$\dfrac{\sqrt{3}}{2}\times 12=\dfrac{h}{12}\times 12$

$6\sqrt{3}=h$

Therefore, the height of the triangle is $6\sqrt{3}$ cm.

3 0

2 years ago

What is the equation of this graphed line?

Arturiano [62]

Answer:

y = -1/3x - 5

Step-by-step explanation:

Use rise over run to find the slope: (y2 - y1) / (x2 - x1)

Plug in the points:

(y2 - y1) / (x2 - x1)

(-7 + 3) / (6 + 6)

-4 / 12

= -1/3

Plug in the slope and a point into y = mx + b, and solve for b:

y = mx + b

-3 = -1/3(-6) + b

-3 = 2 + b

-5 = b

Plug in the slope and b into y = mx + b

y = -1/3x - 5 is the equation of the line

8 0

3 years ago

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