Slope: (y2-y1)/(x2-x1)
(3-3)/(2-10) = 0/-8 = 0
The slope is 0
First you subtract 1/3 from both sides, that leaves you with 5/12, then you multiply the reciprocal of 1/2 by both sides, which is 2, which gives you 5/6. Therefore, K>5/6
I'm going to assume that the room is a rectangle.
The area of a rectangle is A = lw, where l=length of the rectangle and w=width of the rectangle.
You're given that the length, l = (x+5)ft and the width, w = (x+4)ft. You're also told that the area, A = 600 sq. ft. Plug these values into the equation for the area of a rectangle and FOIL to multiply the two factors:

Now subtract 600 from both sides to get a quadratic equation that's equal to zero. That way you can factor the quadratic to find the roots/solutions of your equation. One of the solutions is the value of x that you would use to find the dimensions of the room:

Now you know that x could be -29 or 20. For dimensions, the value of x must give you a positive value for length and width. That means x can only be 20. Plugging x=20 into your equations for the length and width, you get:
Length = x + 5 = 20 + 5 = 25 ft.
Width = x + 4 = 20 + 4 = 24 ft.
The dimensions of your room are 25ft (length) by 24ft (width).
The answer would be the distances that are not too large and not too small
A.legnth and width of a ball room
this would work because the next measurement is 1 mils and ball rooms are not that big
B. width of an eyelash. that is rediculously small so this is wrong
C. distanc from chicaco to san fransisco
way too far, use miles
D. height of a door
corect, door is apout 8 feet aprox
answer is A and D
Answer:
Segment BC = 36 mm or 3.6 cm
Step by Step Explanation:
There are 10 mm in 1 cm
meaning that segment AC is 40 mm long
if AB is 4 mm and it is one part of the two, then we need to subtract that from the total to find out what is left.
40 - 4 = 36
Segment BC = 36 mm or 3.6 cm