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3 years ago

Which of the following possibilities will form a triangle?

Mathematics

2 answers:

zhenek [66]3 years ago

4 0

D will form a triangle

good luck

aleksklad [387]3 years ago

3 0

I'm pretty sure that the correct answer is:
b Side = 15 cm, side = 6 cm, side = 9 cm

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Calculus: Help ASAP

Serggg [28]

$\bf \displaystyle \int\limits_{-1}^{0}~(4x^6+2x)^3(12x^5+1)\cdot dx\\\\
-------------------------------\\\\
u=4x^6+2x\implies \cfrac{du}{dx}=24x^5+2\implies \cfrac{du}{2(12x^5+1)}=dx\\\\
-------------------------------\\\\
\displaystyle \int\limits_{-1}^{0}~u^3\underline{(12x^5+1)}\cdot\cfrac{du}{2\underline{(12x^5+1)}}\implies \cfrac{1}{2}\int\limits_{-1}^{0}~u^3\cdot du\\\\
-------------------------------\\\\$

$\bf \textit{now, we'll change the bounds, using u(x)}
\\\\\\
u(-1)=4(-1)^6+2(-1)\implies u(-1)=2
\\\\\\
u(0)=4(0)^6+2()\implies u(0)=0\\\\
-------------------------------\\\\
\displaystyle \cfrac{1}{2}\int\limits_{2}^{0}~u^3\cdot du\implies \left. \cfrac{1}{2}\cdot \cfrac{u^4}{4} \right]_{2}^{0}\implies \left. \cfrac{u^4}{8} \right]_{2}^{0}\implies [0]-[2]\implies -2$

5 0

2 years ago

Find the area of the shaded region. The radius of the large circle is 10 m. Round answer to the nearest hundredth.

vivado [14]

Answer:

hello the figure related to your question is missing attached below is the missing figure

answer : 157.08 m^2

Step-by-step explanation:

Calculate the area of the shaded area

= Area of the large circle - Areas of the small circles

= (( $\frac{\pi }{4}$ ) * D^2) - 2( ( $\frac{\pi }{4}$ ) * d^2 ) given that the small circles are congruent

= (( $\frac{\pi }{4}$ ) * 20^2 ) - 2 ( ( $\frac{\pi }{4}$ ) * 10^2 )

= 314.16 - 157.08

= 157.08 m^2

8 0

2 years ago

Differentiating a Logarithmic Function in Exercise, find the derivative of the function. See Examples 1, 2, 3, and 4.

adoni [48]

Answer: The required derivative is $\dfrac{8x^2+18x+9}{x(2x+3)^2}$

Step-by-step explanation:

Since we have given that

$y=\ln[x(2x+3)^2]$

Differentiating log function w.r.t. x, we get that

$\dfrac{dy}{dx}=\dfrac{1}{[x(2x+3)^2]}\times [x'(2x+3)^2+(2x+3)^2'x]\\\\\dfrac{dy}{dx}=\dfrac{1}{[x(2x+3)^2]}\times [(2x+3)^2+2x(2x+3)]\\\\\dfrac{dy}{dx}=\dfrac{4x^2+9+12x+4x^2+6x}{x(2x+3)^2}\\\\\dfrac{dy}{dx}=\dfrac{8x^2+18x+9}{x(2x+3)^2}$

Hence, the required derivative is $\dfrac{8x^2+18x+9}{x(2x+3)^2}$

3 0

2 years ago

The box plot on this page shows the total amount of time, in minutes, the students of a class surf the Internet every day:

maxonik [38]

Answer:

It would be Part B

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

What is the value of the expression 18-2x(4+3)

Yanka [14]

Answer:

12-8x

Step-by-step explanation:

18-2x(4+3) =

18 -8x -6 =

12 -8x

3 0

3 years ago