N=1.2 I don't know what you are asking in the second part of the question
Answer:
Step-by-step explanation:
Where's the graph?
Answer:
After 19 months,value in the account will reach $3700
Step-by-step explanation:
The value of a savings account f(t) in terms of t ( number of months since account opening) is given as ![\[3,500(1.003)^{t}\]](https://tex.z-dn.net/?f=%5C%5B3%2C500%281.003%29%5E%7Bt%7D%5C%5D)
We need to determine the value of t when f(t)>=3700
Expressing it in equation form,
![\[3,500(1.003)^{t} >= 3700\]](https://tex.z-dn.net/?f=%5C%5B3%2C500%281.003%29%5E%7Bt%7D%20%3E%3D%203700%5C%5D)
![\[=>(1.003)^{t} >= \frac{3700}{3500}\]](https://tex.z-dn.net/?f=%5C%5B%3D%3E%281.003%29%5E%7Bt%7D%20%3E%3D%20%5Cfrac%7B3700%7D%7B3500%7D%5C%5D)
![\[=>(1.003)^{t} >= 1.057\]](https://tex.z-dn.net/?f=%5C%5B%3D%3E%281.003%29%5E%7Bt%7D%20%3E%3D%201.057%5C%5D)
Taking log of both sides,
![\[=>t * log(1.003) >= log(1.057)\]](https://tex.z-dn.net/?f=%5C%5B%3D%3Et%20%2A%20log%281.003%29%20%3E%3D%20log%281.057%29%5C%5D)
![\[=>t >= \frac{log(1.057)}{log(1.003)}\]](https://tex.z-dn.net/?f=%5C%5B%3D%3Et%20%3E%3D%20%5Cfrac%7Blog%281.057%29%7D%7Blog%281.003%29%7D%5C%5D)
![\[=>t >= 18.51\]](https://tex.z-dn.net/?f=%5C%5B%3D%3Et%20%3E%3D%2018.51%5C%5D)
So t = 19.
Answer:
p is 2.
Step-by-step explanation:
Answer: 
Step-by-step explanation:
Let we consider sales of home in January as first term for sequence, then sales in February will be 2nd term and so on.
According to the given information, we have
First term : 
Second term :
Third term : 
We can see that, Common difference = 7
Explicit rule for Arithmetic sequence :

Put
and d=7

The required explicit rule that can be used to find the number of homes sold in the nth month of the year : 