If x=students, the equation would be x=12 (x is less than of equal to twelve). I don’t know what you mean by constraints; perhaps if you explain more, I could help?
<span>In a jar of ten beads; since 3 are blue; probability of picking a blue ball, B, = p(b) = 3/10. And P (of not picking a blue ball) ; p(b') = 7/10.
Since it occurs with replacement, probabilities doesn't change
Probaility of picking k blue balls from on n attempts is given by P_n(k)
P_n(k) = (n, k) p^(k) q^(n -k) where p and q are b and b' respectively.
P_5(2) = (5 , 2) (0.3)^(2) (0.7)^(5 - 2)
P_5(2) = 5C2 (0.3)^(2) (0.7)^(3) = 0.3087</span>
Answer:
You have to set them equal to each other and then solve for x
Step-by-step explanation:
