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4 years ago

I don't understand this question, picture attached.

Mathematics

1 answer:

mina [271]4 years ago

5 0

We can find this using the formula for arc length (where $r$ is the radius of the circle and $\theta$ is the central angle in radians):

$\textrm{Arc Length} = r\theta$

In our problem, we are given $12 = 8\theta$ . This means that:

$\theta = \dfrac{12}{8} = \boxed{\frac{3}{2}}$

The measure of the angle is 1.5.

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Which pair of expressions are equivalent? 3 v + 5 minus 9 v + 2 and negative 6 v + 6 Negative 6 n + 3 minus 2 n + 2 and negative

hjlf

Answer:

Negative 4 n + 8 + 9 n minus 2 and 5 n + 6

Step-by-step explanation:

3v + 5 - (9v + 2)

3v + 5 - 9v -2 = -6v + 3

-6v + 6

(NO)

-6n + 3 - (2n + 2)

-6n + 3 - 2n - 4 = -8n - 1

-8n + 6

(NO)

-4n + 8 + 9n - 2 = 5n + 6

5n + 6

(YES)

3 0

3 years ago

Read 2 more answers

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IRINA_888 [86]

Answer:

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8 0

3 years ago

Graph for 4x + 3y = -3

Serga [27]

Answer:

Your answer is: Slope = $-\frac{4}{3}$ Y-intercept = $(0,-1)$

Graph the line using the slope and y-intercept, or two points.

Step-by-step explanation:

Graph Below : ↓

Hope this helped : )

6 0

3 years ago

The $1 coin depicts Sacagawea and her infant son. The diameter of the coin is 26.5 mm, and the thickness is 2.00 mm. Find the vo

Contact [7]

Answer

Find the volume of the coin is cubic millimeters.

To prove

Formula

$Volume\ of\ cylinder\ = \pi r^{2} h$

Where r is the radius and h is the height .

As given

The $1 coin depicts Sacagawea and her infant son.

The diameter of the coin is 26.5 mm, and the thickness is 2.00 mm.

$Radius = \frac{Diameter}{2}$

$Radius = \frac{26.5}{2}$

Radius = 13.25 mm

$\pi = 3.14$

Put in the formula

Volume of coin = 3.14 × 13.25 × 13.25 × 2.00

= 1102.53 mm³ (approx)

Therefore the volume of the coin is 1102.53 mm³ .

7 0

4 years ago

Rory's battery was full at 6:00 a.M, or t = 0. Which times could Rory's phone have been plugged into the charger? Select three o

Taya2010 [7]

Complete question:

Rory records the percentage of battery life remaining on his phone throughout a day. The graph represents the percentage of battery life remaining after a certain number of hours.

Rory’s battery was full at 6:00 a.m, or t = 0. Which times could Rory's phone have been plugged into the charger? Select three options.

12:00 p.m.

3:00 p.m.

5:00 p.m.

8:00 p.m.

11:00 p.m.

The graph is attached

Answer:

3:00 p.m

5:00 p.m

11:00 p.m

Step-by-step explanation:

From the graph, there are rise times, fall times and there are times the movement is steady (no rise or fall).

The rise time represents the time the phone was plugged. The fall time represents when the charger has been unplugged so the battery level starts depreciating. When it is constant, it means the battery level is at 100 but the charger is still connected to the phone.

We are told at initial condition, time was 6 a.m (t = 0). To get the exact time, we are to add the initial condition, i.e 6

From the graph, the times the phone could have been plugged are 8:00 to 12:00 hrs and 16:00 to 20:00 hrs.

Converting from 24 hr to 12 hr time, we have:

6 + 8hrs = 14:00 = 2:00 p.m

6 + 9hrs = 15:00 = 3:00 p.m

6 + 10 hrs = 16:00 = 4:00 p.m

6 + 11 hrs = 17:00 = 5:00 p.m

6 + 12 hrs = 18:00 = 6:00 p.m

6 + 16 hrs = 22:00 = 10:00 p.m

6 + 17 hrs = 23:00 = 11:00 p.m

6 + 18 hrs = 00:00 = 12:00 am

6 + 19 = 1 : 00 = 1:00 a.m

6 + 20 = 2:00 = 2:00 a.m

From the options given in the question, we have:

3:00 p.m; 5:00 p.m; 11:00 p.m

Therefore, times could Rory's phone have been plugged into the charger are:

3:00 p.m

5:00 p.m

11:00 p.m

5 0

3 years ago