What is the equation of a line that passes through the point (8, 1) and is perpendicular to the line whose equation is y=−2/3x+5
?
1 answer:
Let
and 

We have 
Therefore

We have the equation of a line:
.
Put the coordinates of the point (8, 1) to the equation of a line:


<em>subtract 11 from both sides</em>

Answer: 
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Step-by-step explanation:
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<u>6 = 6</u>
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<u>y = 3x - 3</u>
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