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PolarNik [594]
3 years ago
14

I'm so confused about this question for homework . Could you help me? The glee club has 120 cupcakes to sell. They have decided

to arrange the cupcakes in the shape of a rectangle, such that the rows have an even number of cupcakes and the columns have an odd number of cupcakes. How many arrangements of cupcakes can they create? Explain.
Mathematics
1 answer:
Alecsey [184]3 years ago
6 0
The number of rows is the length
the nuumber of collumns is the width

alrighty
length times widdth=total number of cupcaces

so we factor 120 to find odd and even pairs
120=1*2*2*2*3*5

so some even and odd pairs are
1*120
3*40
5*24
8*15

those are all the possible pairs

so they can make 4 different arrangements

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Answer:

-54 is a integer and rational number

Step-by-step explanation:

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Nick will move a storage bin from its current location to the new location shown on the coordinate plane. Describe how Nick coul
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Answer:

Move downward by 7 units

Move leftward by 6 units

(x,y) \to (x -6,y-7)

Step-by-step explanation:

Given

See attachment for grid

Required

The transformation from the current location to the new location

To do this, we pick two corresponding points on the current location and the new location.

We have:

A = (3,2) -- Current location

A' = (-6,-5) -- New location

First, move A downwards by 7 units.

The rule to this is:

(x,y) \to (x,y-7)

So, we have:

(3,2) \to (3,2-7)

(3,2) \to (3,-5)

Next, move the above points leftward by 6 units.

The rule to this is:

(x,y) \to (x-6,y)

So, we have:

(3,-5) \to (3-6,-5)

(3,-5) \to (-3,-5)

6 0
2 years ago
(x² + x - 17) ÷ (x - 4)
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Answer:
(X^2 + X-17) /x-4
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Which type of transformation could cause a change in the period of a tangent or cotangent function? vertical shift phase shift v
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7 0
3 years ago
Read 2 more answers
A candidate for a US Representative seat from Indiana hires a polling firm to gauge her percentage of support among voters in he
mojhsa [17]

Answer:

(A) The minimum sample size required achieve the margin of error of 0.04 is 601.

(B) The minimum sample size required achieve a margin of error of 0.02 is 2401.

Step-by-step explanation:

Let us assume that the percentage of support for the candidate, among voters in her district, is 50%.

(A)

The margin of error, <em>MOE</em> = 0.04.

The formula for margin of error is:

MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}

The critical value of <em>z</em> for 95% confidence interval is: z_{\alpha/2}=1.96

Compute the minimum sample size required as follows:

MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}\\0.04=1.96\times \sqrt{\frac{0.50(1-0.50)}{n}}\\(\frac{0.04}{1.96})^{2} =\frac{0.50(1-0.50)}{n}\\n=600.25\approx 601

Thus, the minimum sample size required achieve the margin of error of 0.04 is 601.

(B)

The margin of error, <em>MOE</em> = 0.02.

The formula for margin of error is:

MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}

The critical value of <em>z</em> for 95% confidence interval is: z_{\alpha/2}=1.96

Compute the minimum sample size required as follows:

MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}\\0.02=1.96\times \sqrt{\frac{0.50(1-0.50)}{n}}\\(\frac{0.02}{1.96})^{2} =\frac{0.50(1-0.50)}{n}\\n=2401.00\approx 2401

Thus, the minimum sample size required achieve a margin of error of 0.02 is 2401.

8 0
3 years ago
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