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marishachu [46]
3 years ago
5

wind and weather patterns are caused when warm air near the surface of the earth rises to higher levels in the atmosphere the ai

r movement is called
Mathematics
1 answer:
wolverine [178]3 years ago
6 0
 I believe that is convection
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Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
defon

Answer:  84

<u>Step-by-step explanation:</u>

Set up a proportion as follows: \dfrac{\text{students that practice everyday}}{\text{total students}}

\dfrac{7}{12}=\dfrac{x}{144}

Cross multiply: 12x = 7 × 144

Divide by 12:         x = 7 × 12

Simplify:                x = 84

6 0
3 years ago
Solve for A A/20 = 7
slavikrds [6]

Answer:

A = 140

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Find the slope through the given points Show your work. (2, 3) and (-5, 4)
belka [17]
The answer is (7,-1).

x1-y1 and x2-y2 gives you 2-(-5) and 3-4, so you now have a point which is (7,-1) which is the slope.
7 0
3 years ago
Initial Knowledge Check
Law Incorporation [45]

Answer:

Step-by-step explanation:

We first need to figure out what the equation is for this set of circumstances before we can answer any questions. We will use the equation

A(t)=P(1+r)^t which is just another form of an exponential equation where

(1 + r) is the growth rate, P is the initial investment, and t is the time in years. We will fill in the values we know first to create the equation:

A(t)=4000(1+.11)^t which simplifies to

A(t)=4000(1.11)^t

Now we'll just sub in a 1 for t and solve, then a 2 for t and solve.

When t = 1:

A(t) = 4000(1.11) so

A(t) = 4440

When t = 2:

A(t)=4000(1.11)^2 which simplifies to

A(t) = 4000(1.2321) so

A(t) = 4928.40

4 0
3 years ago
Find the critical values: a. Determine the critical value z????/2 that corresponds to a level of confidence of 87%. (2 pts). b.
larisa86 [58]

Answer:

a) z_{\alpha/2}=-1.51 and z_{\alpha/2}=1.51

b) t_{\alpha/2}=-1.89 and t_{\alpha/2}=1.89

c) t_{\alpha/2}=-2.11

d) z_{\alpha/2}=-1.75 and z_{\alpha/2}=1.75

Step-by-step explanation:

Part a

On this case the confidence is 87% or 0.87 so the significance level is \alpha=1-0.87=0.13 and \alpha/2 =0.065. On this case we can assume that is a bilateral test or a confidence interval so we will have two critical values.

We need values a,b on the normal standard distribution such that:

P(Z or P(Z>b)=0.065 and in order to find it we can use the following code in excel:

"NORM.INV(0.065,0,1)" or "NORM.INV(1-0.065,0,1)", and we see that the critical values z_{\alpha/2}=-1.51 and z_{\alpha/2}=1.51

Part b

On this case the confidence is 92% or 0.92 so the significance level is \alpha=1-0.92=0.08 and \alpha/2 =0.04. On this case we can assume that is a bilateral test or a confidence interval so we will have two critical values.

First we need to calculate the degrees of freedom given by:

df=n-1=15-1=14

We need values b,c on the t distribution with 14 degrees of freddom such that:

P(t_{(14)} or P(t_{(14)}>c)=0.04 and in order to find it we can use the following code in excel:

"T.INV(0.04,14)" or "T.INV(1-0.04,14)", and we see that the critical values t_{\alpha/2}=-1.89 and t_{\alpha/2}=1.89

Part c

The significance level is \alpha=0.025 and is a left tailed test. On this case we know that is a left tailed test so then we have just one critical value.

First we need to calculate the degrees of freedom given by:

df=n-1=18-1=17

We need a value c on the t distribution with 17 degrees of freddom such that:

P(t_{(17)}, and in order to find it we can use the following code in excel:

"T.INV(0.025,17)", and we see that the critical values t_{\alpha/2}=-2.11

Part d

The significance level is \alpha=0.08 and \alpha/2 =0.04. On this case we know that w ehave a two tailed proportion test, so we will have two critical values.

We need values a,b on the normal standard distribution such that:

P(Z or P(Z>b)=0.04 and in order to find it we can use the following code in excel:

"NORM.INV(0.04,0,1)" or "NORM.INV(1-0.04,0,1)", and we see that the critical values z_{\alpha/2}=-1.75 and z_{\alpha/2}=1.75

6 0
3 years ago
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