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3 years ago

14

HELP ASAP WILL MARK BRAINLIEST !!!!

2 answers:

saul85 [17]3 years ago

6 0

Answer:

D. Moles of solute (mol) ÷ liters of solution (L)

Explanation:

Molarity is defined as the no. of moles of solute dissolved in 1.0 L of the solution.

M = (no. of moles)solute / (V of the solution (L))

<em>So, the right choice is: D. Moles of solute (mol) ÷ liters of solution (L)</em>

Anni [7]3 years ago

4 0

<u>Answer:</u> The correct answer is Option D.

<u>Explanation:</u>

Molarity is defined as the number of moles that are present in one liter of solution. This is a term used to express concentration of solute.

The equation used to calculate molarity of solution is:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Thus, the correct answer will be Option D.

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100.0 g water cools from 85.0°C to 20.0°C. If the specific heat of water is 4.18 J/g°C, calculate the change in energy.

Natali5045456 [20]

Answer:

-27.2 kJ

Explanation:

We can use the heat-transfer formula. Recall that:

$\displaystyle q = mC\Delta T$

Where <em>m</em> is the mass, <em>C</em> is the substance's specific heat, and Δ<em>T</em> is the change in temperature.

Hence substitute:

$\displaystyle \begin{aligned} q & = (100.0\text{ g})\left(\frac{4.18\text{ J}}{\text{g-$^\circ$C}}\right)(20.0\text{ $^\circ$C} - 85.0\text{ $^\circ$C}) \\ \\ & =(100.0\text{ g})\left(\frac{4.18\text{ J}}{\text{g-$^\circ$C}}\right)(-65.0\text{ $^\circ$C}) \\ \\ & = -2.72\times 10^4\text{ J} = -27.2\text{ kJ}\end{aligned}$

Therefore, the cooling of the water <em>released</em> about 27.2 kJ of heat.

5 0

3 years ago

What is the mass of 1.00 mol of oxygen (O2)?

Ad libitum [116K]

Answer:

Mass = 32 g

Explanation:

Given data:

Number of moles of oxygen = 1.0 mol

Mass of oxygen = ?

Solution:

Formula:

Number of moles = mass/molar mass

Molar mass of oxygen (O₂) is 32 g/mol

by putting values,

1.0 mol = mass/ 32 g/mol

Mass = 1.0 mol ×32 g/mol

Mass = 32 g

4 0

3 years ago

What is the freezing point (in °C) of a 0.743 m

luda_lava [24]

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7 0

3 years ago

Calculate ΔGrxn at 298 K under the conditions shown below for the following reaction.

algol13

Answer : The value of $\Delta G_{rxn}$ is -24.9 kJ/mol

Explanation :

First we have to calculate the value of 'Q'.

The given balanced chemical reaction is,

$Fe_2O_3(s)+3CO(g)\rightarrow 2Fe(s)+3CO_2(g)$

The expression for reaction quotient will be :

$Q=\frac{(p_{CO_2})^3}{(p_{CO})^3}$

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

$Q=\frac{(2.1)^3}{(1.4)^2}$

$Q=3.375$

Now we have to calculate the value of $\Delta G_{rxn}$ .

The formula used for $\Delta G_{rxn}$ is:

$\Delta G_{rxn}=\Delta G^o+RT\ln Q$ ............(1)

where,

$\Delta G_{rxn}$ = Gibbs free energy for the reaction = ?

$\Delta G_^o$ = standard Gibbs free energy = -28.0 kJ/mol

R = gas constant = $8.314\times 10^{-3}kJ/mole.K$

T = temperature = 298 K

Q = reaction quotient = 3.375

Now put all the given values in the above formula 1, we get:

$\Delta G_{rxn}=(-28.0kJ/mol)+[(8.314\times 10^{-3}kJ/mole.K)\times (298K)\times \ln (3.375)$

$\Delta G_{rxn}=-24.9kJ/mol$

Therefore, the value of $\Delta G_{rxn}$ is -24.9 kJ/mol

5 0

3 years ago

When liquid water changes into solid ice, it increases in ?

kramer

when liquid water changes into solid ice, it increases in mass

8 0

3 years ago

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