Bohr model of an atom illustrates a nucleus with electrons circling around it. This is a useful model for understanding atoms because this clarified that atoms are actually composed of three particles: protons, neutrons and electrons. The first two are located at the center part of an atom (nucleus), while electrons are located at the outer part. Valence electrons of an atom are also vital in the creation of different chemical compounds.
Answer:
The atom is oxidized is Ca.
Explanation:
- The oxidation-reduction reaction contains a reductant and an oxidant (oxidizing agent).
- The oxidation process is the process in which electrons are lost and produce positively charged ions.
- The reduction process is the process in which electrons is gained and negatively charge ions are produced.
- In the reaction of chlorine with calcium:
<em>Ca + Cl₂ → CaCl₂,</em>
Ca loses 2 electrons and is oxidized to Ca²⁺. (Ca <em>→</em> Ca²⁺ + 2e).
Cl is gains 2 electrons in "Cl₂, oxidation state zero" and is reduced to Cl⁻. (Cl₂ + 2e <em>→</em> 2Cl⁻).
S₂O₈²⁻
(aq) + 2I⁻
(aq) → I₂(aq) + 2SO₄
²⁻(aq)
2S₂O₃²⁻
(aq) + I₂(aq) → S₄O₆²⁻
(aq) + 2I⁻
(aq)
<u>Explanation:</u>
S₂O₈²⁻
(aq) + 2I⁻
(aq) → I₂(aq) + 2SO₄
²⁻(aq)
To measure the rate of this reaction we must measure the rate of concentration change of one of the reactants or products. To do this, we will include (to the reacting S₂O₈
²⁻ and I⁻
i) a small amount of sodium thiosulfate, Na₂S₂O₃,
ii) some starch indicator.
The added Na₂S₂O₃ does not interfere with the rate of above reaction, but it does consume the I₂ as soon as it is formed.
2S₂O₃²⁻
(aq) + I₂(aq) → S₄O₆²⁻
(aq) + 2I⁻
(aq)
This reaction is much faster than the previous, so the conversion of I2 back to I⁻ is essentially instantaneous.
Answer:
Explanation:
- The chemical reaction for cellular respiration is as follows -
C₆H₁₂O₆ ( Glucose ) + 6 O₂ ( Oxygen ) --------------> 6CO₂ ( Carbon dioxide ) + 6H₂O ( Water ) + 38 ATP molecules ( Energy ) .
This is an example of oxidation of carbon .
- The chemical reaction for photosynthesis is as follows -
6CO₂ ( Carbon dioxide ) + 6H₂O ( Water ) --------------> C₆H₁₂O₆( Glucose ) + 6 O₂ ( Oxygen ).
This is an example of reduction of carbon .
Answer:
a. CH3NH2(aq) + H⁺ → CH3NH3⁺
Explanation:
The mixture of a weak base as CH3NH2 with its conjugate acid CH3NH3Cl produce a buffer. As the weak acid is in equilibrium with water, the mixture of the weak base and its conjugate base produce that the acid or base released react avoiding the change in pH.
For example, when a strong acid as HNO3 reacts, the weak base will react producing the conjugate base, that is:
CH3NH2(aq) + H⁺ → CH3NH3⁺
Right answer is:
<h3>a. CH3NH2(aq) + H⁺ → CH3NH3⁺</h3>