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Verizon [17]
3 years ago
5

Find the of the line

Mathematics
1 answer:
Umnica [9.8K]3 years ago
7 0

Answer:

D

Step-by-step explanation:

Using the Slope Equation

Pick two points on the line and determine their coordinates.

Determine the difference in y-coordinates of these two points (rise).

Determine the difference in x-coordinates for these two points (run).

Divide the difference in y-coordinates by the difference in x-coordinates (rise/run or slope

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1/6 × 3/5<br> 3/4× 7/9<br> 3/7× 2/3<br> 7/10× 8/21<br> 4/5× 2/7<br> 6/7× 1/6 in simplest form.
slamgirl [31]
1/6times 3/5=1/10

3/4 times 7/9=7/9

3/7 times 2/3= 2/7

7/10 times 8/21=???

4/5 times 2/7=8/35

6/7 times 1/6=1/7
3 0
3 years ago
A paintball Court Tarzan an initial entrance fee plus a fixed price for all the variable P models the total price (in dollars) a
Marizza181 [45]

Answer:

that

Step-by-step explanation:

tat

5 0
3 years ago
The answer to this problem?
LenaWriter [7]

The simplified expression of \sqrt{\frac{162x^9}{2x^{27}}} is \frac{9}{x^9}

<h3>How to simplify the expression?</h3>

The expression is given as:

\sqrt{\frac{162x^9}{2x^{27}}}

Divide 162 and 2 by 2

\sqrt{\frac{81x^9}{x^{27}}}

Take the square root of 81

9\sqrt{\frac{x^9}{x^{27}}}

Apply the quotient rule of indices

9\sqrt{\frac{1}{x^{27-9}}}

Evaluate the difference

9\sqrt{\frac{1}{x^{18}}}

Take the square root of x^18

\frac{9}{x^9}

Hence, the simplified expression of \sqrt{\frac{162x^9}{2x^{27}}} is \frac{9}{x^9}

Read more about expressions at:

brainly.com/question/723406

#SPJ1

5 0
2 years ago
What pattern can i say here 2,5,11,23,47
Vilka [71]

Answer:

Your rule is: Multiply 2, Add 1

Step-by-step explanation:

Check:

2 x 2 = 4 + 1 = 5

5 x 2 = 10 + 1 = 11

11 x 2 = 22 + 1 = 23

23 x 2 = 46 + 1 = 47

~

3 0
4 years ago
Read 2 more answers
Please solve this question
Mandarinka [93]

Answer:

46?

Step-by-step explanation:

23*2=46

3 0
2 years ago
Read 2 more answers
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