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konstantin123 [22]
3 years ago
15

An Austrian study was completed to determine if untrained sea lions and sea lionesses could follow various experimenter-given cu

es when given a choice of two objects. One experimenter-given cue was to point at one of the objects. One sea lioness, named Zwerg, successfully chose the pointed-at object 37 times out of 48 trials. Does this result show that Zwerg can correctly follow this type of direction by an experimenter more than 50% of the time?ââ
Mathematics
1 answer:
Sholpan [36]2 years ago
3 0

Using the z-distribution, it is found that since the test statistic is greater than the critical value for the right-tailed test, this result shows that Zwerg can correctly follow this type of direction by an experimenter more than 50% of the time.

<h3>What are the hypothesis?</h3>
  • At the null hypothesis, it is tested if Zwerg cannot correctly follow this type of direction by an experimenter more than 50% of the time, that is:

H_0: p \leq 0.5

  • At the alternative hypothesis, it is tested if Zwerg can correctly follow this type of direction by an experimenter more than 50% of the time, that is:

H_1: p > 0.5

<h3>Test statistic</h3>

The <em>test statistic</em> is given by:

z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}

In which:

  • \overline{p} is the sample proportion.
  • p is the proportion tested at the null hypothesis.
  • n is the sample size.

For this problem, the parameters are:

n = 48, \overline{p} = \frac{37}{48} = 0.7708, p = 0.5

The value of the <em>test statistic</em> is:

z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}

z = \frac{0.7708 - 0.5}{\sqrt{\frac{0.5(0.5)}{48}}}

z = 3.75

Considering a <u>right-tailed test</u>, as we are testing if the proportion is greater than a value, with a <u>significance level of 0.05</u>, the critical value for the z-distribution is z^{\ast} = 1.645.

Since the test statistic is greater than the critical value for the right-tailed test, this result shows that Zwerg can correctly follow this type of direction by an experimenter more than 50% of the time.

To learn more about the z-distribution, you can take a look at brainly.com/question/16313918

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