What is 7 +2 = x-4/2
1 answer:
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Equation of a line:
m = gradient: The difference between two y points and two x points.
c = y-intercept: Where the line crosses the y-axis (x=0)
You have:
so you are missing the m and the c.
To calculate m find two y coordinates -you have (12, <u>7</u>) and (0, <u>1</u>)- and subtract them. Then divide this by the subtracted values of the x coordinates -you have (<u>12</u>, 7) and (<u>0</u>, 1)- This gives:
To calculate the c, you just see where the line crosses the y-axis. Because you have the point (0, 1), you know that when x=0, y=1. Because x=0 is on the y-axis, you can tell that the line passes through y=1. This makes your c = 1:
When you plug these values into the equation you get your answer:
m = gradient: The difference between two y points and two x points.
c = y-intercept: Where the line crosses the y-axis (x=0)
You have:
so you are missing the m and the c.
To calculate m find two y coordinates -you have (12, <u>7</u>) and (0, <u>1</u>)- and subtract them. Then divide this by the subtracted values of the x coordinates -you have (<u>12</u>, 7) and (<u>0</u>, 1)- This gives:
To calculate the c, you just see where the line crosses the y-axis. Because you have the point (0, 1), you know that when x=0, y=1. Because x=0 is on the y-axis, you can tell that the line passes through y=1. This makes your c = 1:
When you plug these values into the equation you get your answer:
we conclude that the center of the circle is the point (-5, 0).
<h3>How to find the center of the circle equation?</h3>The equation of a circle with a center (a, b) and a radius R is given by:
Here we are given the equation:
Completing squares, we get:
Now we can add and subtract 25 to get:
Comparing that with the general circle equation, we conclude that the center of the circle is the point (-5, 0).
If you want to learn more about circles:
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