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Alisiya [41]
2 years ago
8

The number of students taking algebra increased 20% in one year. If

Mathematics
1 answer:
Fiesta28 [93]2 years ago
7 0

Answer: 50 students

Step-by-step explanation:

You know that the number of students last year plus 20% of that number equals the number of students this year, which can be written as: x + 0.2x = 60 →

1.2x = 60 → x = 50 students :)

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Adam drove 280 miles in 4 hours. On average, how fast did he drive in hours per mile? Express your answer in simplest form.
Natasha2012 [34]

Answer:

1/70  hours per mile

Step-by-step explanation:

We want hours per mile

Take the hours and divide by the miles

4 hours / 280 miles

1 hours/ 70 miles

7 0
3 years ago
Read 2 more answers
Find four consecutive even integers such that the sum of the second and fourth and integer is one half times the sum of the firs
Artyom0805 [142]
Okay lets create an eqn from that information

A first int, B second int, C third int, D fourth int.

B = A + 2
C = A + 4
D = A + 6
A is the smallest integer

B + D = 0.5 (A + C) 

Now lets substitute

(A + 2) + (A + 6) = 0.5(A + (A + 4))
now lets dist

2a + 8 = 0.5(2a +4)
2a + 8 = a + 2
a + 8 = 2
a = -6

B = -6 +2
B = -4
C = -6 + 4
C = -2
D = -6 + 6
D = 0

Now using B + D = 0.5(A + C)
-4 + 0 = 0.5(-6 + (-2))
-4 = 0.5 (-8)
-4 = -4

Correct 
Therefore, First integer is -6, second integer is -4, third integer is -2 and fourth integer is 0
8 0
4 years ago
How to find vertex form with vertex: (3,6) and y intercept: 2
bekas [8.4K]

Answer:

<h3>              f(x) = - ⁴/₉(x - 3)² + 6</h3>

Step-by-step explanation:

The vertex form of  the equation of the parabola with vertex (h, k)  is:

f(x) = a(x - h)² + k

So for vertex (3, 6) it will be:

f(x) = a(x - 3)² + 6

<u>y intercept: 2</u> means  f(0) = 2

f(0) = a(0 - 3)² + 6

2 = a(-3)² + 6

2 -6 = 9a + 6 -6

-4 = 9a

a = ⁻⁴/₉

Therefore:

The vertex form of quardatic function with vertex: (3,6) and y intercept: 2 is

                             <u>f(x) = - ⁴/₉(x - 3)² + 6</u>

5 0
3 years ago
5<br> 0 = - in<br> =<br> in quadrant II<br> Given cos =<br> Find sin<br> 3
____ [38]

Answer:

sinΘ = \frac{2}{3}

Step-by-step explanation:

using the identity

sin²x + cos²x = 1  ( subtract cos²x from both sides )

sin²x = 1 - cos²x ( take square root of both sides )

sinx = ± \sqrt{1-cos^2x}

given

cosΘ = - \frac{\sqrt{5} }{3} , then

sinΘ = ± \sqrt{1-(-\frac{\sqrt{5} }{3})^2 }

        = ± \sqrt{1-\frac{5}{9} }

        = ± \sqrt{\frac{4}{9} }

        = ± \frac{2}{3}

since Θ is in quadrant II where sinΘ > 0 , then

sinΘ = \frac{2}{3}

7 0
3 years ago
A line intersects the points (-1, 3) and
olya-2409 [2.1K]

Answer:

I was able to get: y = -(6/3)x + 1

4 0
3 years ago
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