Answer:
C) {(3, 4), (3, 5)}
Step-by-step explanation:
We know that,
<em>'Function is a relation in which every element of the domain is mapped to a unique element in the co-domain'.</em>
So, we get that,
<em>In the ordered pair (x,y), the if 'x' is mapped to two values say y and z, then for the relation to be a function, y must be equal to z.</em>
So, according to the options, we see that,
In option C i.e. the relation {(3,4), (3.5)}, we have that, 3 does not have unique image i.e. it is mapped to 4 and 5 both.
Thus, this relation does not satisfy the definition of a function.
So, option C will not represent a function.
Answer:
M (0, 6)
Step-by-step explanation:
By midpoint formula,
M [(x1+x2)/2 , (y1+y2)/2]
M [-5+5/2 , 3+9/2]
M (0/2 , 12/2)
M (0, 6)
Answer: B
Step-by-step explanation:
9514 1404 393
Answer:
- Constraints: x + y ≤ 250; 250x +400y ≤ 70000; x ≥ 0; y ≥ 0
- Objective formula: p = 45x +50y
- 200 YuuMi and 50 ZBox should be stocked
- maximum profit is $11,500
Step-by-step explanation:
Let x and y represent the numbers of YuuMi and ZBox consoles, respectively. The inventory cost must be at most 70,000, so that constraint is ...
250x +400y ≤ 70000
The number sold will be at most 250 units, so that constraint is ...
x + y ≤ 250
Additionally, we require x ≥ 0 and y ≥ 0.
__
A profit of 295-250 = 45 is made on each YuuMi, and a profit of 450-400 = 50 is made on each ZBox. So, if we want to maximize profit, our objective function is ...
profit = 45x +50y
__
A graph is shown in the attachment. The vertex of the feasible region that maximizes profit is (x, y) = (200, 50).
200 YuuMi and 50 ZBox consoles should be stocked to maximize profit. The maximum monthly profit is $11,500.