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oee [108]
3 years ago
7

Inverse of g(x) 2x+3

Mathematics
1 answer:
hoa [83]3 years ago
4 0
G^-1(x)=x/2-3/2. Let me know if I was correct
You might be interested in
Question 3 (Multiples and Factors] Three numbers are given below. Use prime factorisation to determine the HCF and LCM 1848 132
Ilia_Sergeevich [38]

Prime factorization involves rewriting numbers as products

The HCF and the LCM of 1848, 132 and 462​ are 66 and 1848 respectively

<h3>How to determine the HCF</h3>

The numbers are given as: 1848, 132 and 462

Using prime factorization, the numbers can be rewritten as:

1848 = 2^3 * 3 * 7 * 11

132 =  2^2 * 3 * 11

462 = 2 * 3 * 7 * 11

The HCF is the product of the highest factors

So, the HCF is:

HCF = 2 * 3 * 11

HCF = 66

<h3>How to determine the LCM</h3>

In (a), we have:

1848 = 2^3 * 3 * 7 * 11

132 =  2^2 * 3 * 11

462 = 2 * 3 * 7 * 11

So, the LCM is:

LCM = 2^3 * 3 * 7 * 11

LCM  = 1848

Hence, the HCF and the LCM of 1848, 132 and 462​ are 66 and 1848 respectively

Read more about prime factorization at:

brainly.com/question/9523814

4 0
2 years ago
Write the equation of the line that passes through the points (-6,1) and (-2,5). Put your answer in fully reduced point-slope fo
irinina [24]
  • (-6,1)
  • (-2,5)

Slope:-

\\ \sf\longmapsto m=\dfrac{5-1}{-2+6}=\dfrac{4}{4}=1

Point-Slope form

\\ \sf\longmapsto y-y_1=m(x-x_1)

\\ \sf\longmapsto y-1=1(x+6)

\\ \sf\longmapsto y-1=x+6

\\ \sf\longmapsto x-y+7=0

3 0
3 years ago
In AEFG, F = 61 inches, ZF=79º and ZG=34°. Find the length of g, to the nearest<br> 10th of an inch.
DENIUS [597]

Answer:

  g ≈ 34.7 in

Step-by-step explanation:

The law of sines is useful for this:

  f/sin(F) = g/sin(G)

Multiplying by sin(G), we have ...

  g = f·sin(G)/sin(F) = (61 in)·sin(34°)/sin(79°)

  g ≈ 34.7 in

7 0
3 years ago
Which expressions are equivalent?
Hatshy [7]

Answer:

3(a-b) and 3a-3b. Equivalent

2a(2+b) and 4ab. Not equivalent

Step-by-step explanation:

hope this helps:)

6 0
3 years ago
Read 2 more answers
Use properties to find the sum or product. <br> 93+(68+7)
erma4kov [3.2K]
93+(68+7)=93+68+7\\use\ commutative\ property: a+b=b+a\\\\=93+7+68\\use\ associative\ property:a+(b+c)=(a+b)+c\\\\=(93+7)+68=100+68=\huge\boxed{168}
6 0
3 years ago
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