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Fed [463]
3 years ago
8

Ejiro is 8yrs older than her sister the sum of their ages is64yrs what is ejiro age in years​

Mathematics
2 answers:
Alika [10]3 years ago
8 0

Answer:

36

Step-by-step explanation:

Ejiro + her sister's age = 64

Ejiro is 8 years older so (64 - 8) ÷ 2 = 28 her sister is 28 years old and ejiro is 28 + 8 = 36 years old

Arlecino [84]3 years ago
6 0

Answer:

She is 36 years old.

Step-by-step explanation:

Ejiro is 8 years older so (64 - 8) ÷ 2 = 28 her sister is 28 years old and ejiro is 28 + 8 = 36 years old

Can I have brainliest???

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Which expressions are equal to 0 when x=-1? Check all that apply.
Reptile [31]

Answer:

4(x+1)/(4x+5)

4(x+1)/(5-4x)​

4(x-(-1))/(4x+5)

Step-by-step explanation:

The numerators in the fractions must equal to 0, or else the expressions won’t have the result of 0.

4(x+1)

4(-1+1)

4(0)

= 0

4(x-(-1))

4(-1-(-1))

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The expressions with the numerator as 0 have the result of 0.

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3 years ago
Order -4,9 -7 -10, and -3 from least to greatest.
vovikov84 [41]

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-10,-7,-4,-3,9

Step-by-step explanation:

7 0
4 years ago
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How far apart are cities A and B in the new map?
Lubov Fominskaja [6]

Answer:

22.5 miles

Step-by-step explanation:

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7.5 x 3=22.5 miles.

5 0
3 years ago
What is the kinetic energy of an object of mass of 30 K moving with a speed of 15 M/S2
ale4655 [162]

You literally need to apply the formula

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5 0
3 years ago
The number of failures of a testing instrument from contamination particles on the product is a Poisson random variable with a m
Mazyrski [523]

Answer:

The probability that the instrument does not fail in an 8-hour shift is P(X=0) \approx 0.8659

The probability of at least 1 failure in a 24-hour day is P(X\geq 1 )\approx 0.3508

Step-by-step explanation:

The probability distribution of a Poisson random variable X representing the number of successes occurring in a given time interval or a specified region of space is given by the formula:

P(X)=\frac{e^{-\mu}\mu^x}{x!}

Let X be the number of failures of a testing instrument.

We know that the mean \mu = 0.018 failures per hour.

(a) To find the probability that the instrument does not fail in an 8-hour shift, you need to:

For an 8-hour shift, the mean is \mu=8\cdot 0.018=0.144

P(X=0)=\frac{e^{-0.144}0.144^0}{0!}\\\\P(X=0) \approx 0.8659

(b) To find the probability of at least 1 failure in a 24-hour day, you need to:

For a 24-hour day, the mean is \mu=24\cdot 0.018=0.432

P(X\geq 1 )=1-P(X=0)\\\\P(X\geq 1 )=1-\frac{e^{-0.432}0.432^0}{0!}\\\\P(X\geq 1 )\approx 0.3508

3 0
3 years ago
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