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Sedbober [7]
3 years ago
7

Write the equation of a line that passes through (-4,15) and (-7,10) in point slope form

Mathematics
1 answer:
Ivanshal [37]3 years ago
8 0
(-4,15),(-7,10)
slope = (10 - 15) / (-7 - (-4) = -5 / (-7 + 4) = -5 / -3 = 5/3

there can be 2 answers to this...depending on the point u use...
y - y1 = m(x - x1)
slope(m) = 5/3
using point (-4,15)...x1 = -4 and y1 = 15
now we sub
y - 15 = 5/3(x - (-4)..not done yet
y - 15 = 5/3(x + 4) <=== this is one answer

y - y1 = m(x - x1)
slope(m) = 5/3
using point (-7,10)....x1 = -7 and y1 = 10
now we sub
y - 10 = 5/3(x - (-7)...not done yet
y - 10 = 5/3(x + 7) <=== and here is the other answer
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2 years ago
I will give lot of points please help
zheka24 [161]

Answer:

V = 43323 mm³

(second answer is already correct)

Step-by-step explanation:

these pennies make up the shape of a cylinder, so, we can solve this question by solving for the volume of a cylinder.

the volume of a cylinder can be found with the formula:

V = πr²h

(V = volume ; π = pi ; r = radius ; h = height)

We know the diameter of this cylinder is 19.05 mm. Diameter is two times the length of the radius, (diameter is all the way across, radius is from center to outer / halfway across) meaning that we can find the radius by dividing 19.05 by 2.

diameter = 19.05

radius = 19.05 / 2 = 9.525

so, r = 9.525

we also are given the height of this cylinder, 38 mm

so, h = 38

π = 3.14159 (π is a constant)

plugging our measurements into the volume formula:

 V = πr²h

V = (3.14159)(9.525²)(38)

V =  (3.14159)(362.9025)(38)

V = 43323.4894628

[rounded to V = 43323 mm³]

And yes, the volume is not affected by a change in shape. (you are correct)

hope this helps!!

4 0
2 years ago
Read 2 more answers
(a) How many integers from 1 through 1,000 are multiples of 2 or multiples of 9?
DENIUS [597]

Answer:

(a)There are 500 integers from 1 through 1,000 are multiples of 2.

There are 111 integers from 1 through 1,000 are multiples of 9.

(b)0.611

Step-by-step explanation:

Given the set of Integers from 1 through 1000

The least multiple of 2 is 2 and the highest multiple of 2 in the interval is 1000.

To determine the number of terms, we use the formula for the nth term of an Arithmetic Progression, since 2,4,6,... is an Arithmetic Progression,

where first term, a =2, common difference, d =2

Nth term of an A.P,

U_n= a+(n-1)d\\1000=2+2(n-1)\\1000=2+2n-2\\1000=2n\\n=500

  • There are 500 integers from 1 through 1,000 are multiples of 2.

Similarly,

Given the set of Integers from 1 through 1000

The least multiple of 9 is 9 and the highest multiple of 9 in the interval is 999.

To determine the number of terms, we use the formula for the nth term of an Arithmetic Progression, since 9,18,27,... is an Arithmetic Progression,

where first term, a =9, common difference, d =9

Nth term of an A.P,

U_n= a+(n-1)d\\999=9+9(n-1)\\999=9+9n-9\\999=9n\\n=111

  • There are 111 integers from 1 through 1,000 are multiples of 9.

(b)Probability that an integer selected at random is a multiple of 2 or a multiple of 9.

There are a total of 1000 numbers between from 1 through 1,000

n(S)=1000

n(Multiples of 2)=500

n(Multiples of 9)=111

Therefore:

P(\text{Multiples of 9}) \:OR\: P(\text{Multiples of 2})=\frac{111}{1000} + \frac{500}{1000} \\=\frac{611}{1000} \\=0.611

7 0
3 years ago
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Lelu [443]

You need to elaborate more. what is each side marked with? What are the answers to pick from. ECT.

7 0
3 years ago
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givi [52]
Which expression is equivalent to 100 n2 − 1? (10n)2 − (1)2 (10n2)2 − (1)2 (50n)2 − (1)2 (50n2)2 − (1)2

Regroup:
100n^2-1

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So the correct answer is : 
(10n)^2-1^2

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3 years ago
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