Answer:
a is height
b is length
c is width
Step-by-step explanation:
Answer:
40/ or /80
Step-by-step explanation:
Because 400 is a lot and if it's 100% is 400 right so we do 80% what would that be? we don't know right.
What about 100 pages that would be (im pretty sure) 40% or 50%.
I hope this helped!!!
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Answer:
A task time of 177.125s qualify individuals for such training.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by
After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.
In this problem, we have that:
A distribution that can be approximated by a normal distribution with a mean value of 145 sec and a standard deviation of 25 sec, so 
.
The fastest 10% are to be given advanced training. What task times qualify individuals for such training?
This is the value of X when Z has a pvalue of 0.90.
Z has a pvalue of 0.90 when it is between 1.28 and 1.29. So we want to find X when 
.
So
A task time of 177.125s qualify individuals for such training.
When a customer has a 6 pound Chihuahua, the cost that will be charged is $5.00.
<h3>How to calculate the cost?</h3>
a. If a customer has a 6 pound Chihuahua, how much would you charge?
It should be noted that from the information given, for dogs that weigh 0 to 15 pounds, the amount charged is $5.00.
b. If a customer has a 65 pound Labrador, how much would you charge?
It should be noted that for dogs over 45 pounds, the amount that's charged is $9.00
There, the amount charged will be $9.00.
Learn more about cost on:
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Answer:
(x² − 2x + 2) (x − 1)
Step-by-step explanation:
Use grouping.
x³ − 3x² + 4x − 2
x³ − 3x² + 2x + 2x − 2
x (x² − 3x + 2) + 2 (x − 1)
x (x − 2) (x − 1) + 2 (x − 1)
(x (x − 2) + 2) (x − 1)
(x² − 2x + 2) (x − 1)
