Answer:
h'(x) = (-x² ln x + x² + 1) / (x (x² + 1)^(³/₂))
Step-by-step explanation:
h(x) = ln x / √(x² + 1)
You can either use quotient rule, or you can rewrite using negative exponents and use product rule.
h(x) = (ln x) (x² + 1)^(-½)
h'(x) = (ln x) (-½) (x² + 1)^(-³/₂) (2x) + (1/x) (x² + 1)^(-½)
h'(x) = (-x ln x) (x² + 1)^(-³/₂) + (1/x) (x² + 1)^(-½)
h'(x) = (x² + 1)^(-³/₂) (-x ln x + (1/x) (x² + 1))
h'(x) = (1/x) (x² + 1)^(-³/₂) (-x² ln x + x² + 1)
h'(x) = (-x² ln x + x² + 1) / (x (x² + 1)^(³/₂))
What do you need to find tho? Comment and I’ll tell you
4x+y=16 multiply both sides by -3 and will get
2x+3y=-2
-12x -3y = -48
2x +3y = -2
--------------------------
-10x 0 = -50
-10x = -50
x = -50/(-10) = 5
x = 5
4x+y=16
4*5+y=16
20+y=16
y = 16-20
y = -4
x = 5
y = - 4
hope helped
-6a-48 that would be it because you are only distributing the -6
Answer:
5 months
Step-by-step explanation:
Jason's original weight = 120 pounds
Let the no. of months be m
If he gains 10 pounds in each moth , then his weight in m months will be = 10m
His total weight will be= 120+10m -----(1)
Gerardo's original weight = 150 pounds
If he gains 4 pounds in each month , then his weight in m months will me =4m
His total weight will be = 150+4m-----(2)
<u>Equating (1) ans(2)</u>
120+10m=150+4m
=>10m-4m=150-120
=>6m=30
=>m=
<u>=>m=5</u>
It will take 5 months for Jason to weigh the same as Gerardo
