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raketka [301]
4 years ago
9

PLS HELP WILL GIVE BRAINLIEST AND 99 POINTS!!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
seropon [69]4 years ago
8 0

Answer:

I KNOW

Step-by-step explanation:

andrew-mc [135]4 years ago
6 0

Answer:You can put this solution on YOUR website!

The numbers are between +/- 2 sd s of the mean

With Chebyshev's inequality, at least 3/4 of the numbers would be between these two.

For the one with 3 standard deviations, it would be 8/9.

----------------------

For the second part, this is 3.5 sd s on either side

1/(3.5)^2=0.0816, The fraction is 1/(49/4) or 4/49.

----------------

The second one would be wishing 18/8 or 2.25 sd s and that fraction would be 1/(9/4)^2=1/81/16 or 16/81 or 0.1975.

Step-by-step explanation:

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The answer is 75 foot
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4 years ago
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Please do one for 3-5 and one for 6-8 i will give brainliest
scoray [572]

Answer:

Use the arithmetic formal

Step-by-step explanation:

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4 0
3 years ago
Work out the formula for the nth term of the<br> quadratic sequence:<br> 19, 15, 9, 1...
Leto [7]

Answer:

Tn = -n^2 - n + 21 is the formula for the nth term.

Step-by-step explanation:

The second differences are all equal in this quadratic sequence.

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Find the value of a in an^2 by dividing the difference by 2:

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5 0
3 years ago
Read 2 more answers
A chemical company makes two brands of antifreeze. The first brand is 30% pure antifreeze and the second brand is 55% pure antif
Phantasy [73]

Answer:

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  • 96 gallons 55%

Step-by-step explanation:

The amount of each brand can be found by writing and solving an equation that makes use of the given relations.

<h3>Setup</h3>

Let x represent the quantity of 55% pure antifreeze needed in the mixture. Then the quantity of the 30% brand is (160-x). The amount of pure antifreeze in the mixture is ...

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<h3>Solution</h3>

Subtracting 0.30(160), we have ...

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Read more about mixture problems here:

brainly.com/question/26751698

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How is the product related to the first factor?  × 
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Answer:

The product is greater than

Step-by-step explanation:


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3 years ago
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