Answer:
-2
Step-by-step explanation:
Answer:
Functions: Second Graph
The other two are not. Use the vertical line test. I'm pretty sure but not 100%
Step-by-step explanation:
Let
L----------> <span>the length of the yard
W--------> </span><span>the width l of the yard
we know that
the perimeter is equal to
</span>
![P=2*[W+L]](https://tex.z-dn.net/?f=P%3D2%2A%5BW%2BL%5D)
![72=2*[W+L] \\ 36=W+L](https://tex.z-dn.net/?f=72%3D2%2A%5BW%2BL%5D%20%5C%5C%2036%3DW%2BL)
--------> equation 1

------> equation 2
<span>substitute equation 2 in equation 1
</span>



<span>
we know that
Area of the rectangular yard is equal to
</span>

<span>
</span>
Answer:
33i - 12
Step-by-step explanation:

Let's use our largest amount (quarter) to see how many can fit evenly into 1.74.
- 1.74/0.25 = 6.96
- The most quarters that can fit into $1.74 is 6.
---Multiply $0.25 by 6 = $1.50
---Subtract $1.50 from $1.74 = $0.24
---We need to use the rest of the coins to fill up $0.24.
Now let's use our second largest amount (dime) to see how many can fit evenly into 0.24.
- 0.24/0.10 = 2.4
- The most dimes that can fit into $0.24 is 2.
---Multiply $0.10 by 2 = $0.20
---Subtract $0.20 from $0.24 = $0.04
No nickels can fit into $0.04, because they are worth $0.05.
We can use our least amount (pennies) to fill in the $0.04 remaining.
Your answer is 6 quarters, 2 dimes, and 4 pennies.