The temperature of the compound will follow this function: 1/8x^2+15 ( I could be wrong).
But how did I come up with this function ??
The standard of a quadratic equation is given...the x is given...the f(x) is given. Now plug these in correspondence to find the constants. The rest is algebra. If you are not getting this answer, let me see your work
Answer:
2/7 is already in the simplest form. It can be written as 0.285714 in decimal form (rounded to 6 decimal places).
Answer:
first one
Step-by-step explanation:
Answer:
<h2>A)t=6.7</h2>
Step-by-step explanation:
<h3>to understand this</h3><h3>you need to know about:</h3>
- quadratic equation
- quadratic equation word problems
- solving quadratic
<h3>given:</h3>
h(t) = -4t² + 12t + 100
<h3>to solve:</h3>
t
<h3>tips and formulas:</h3>
- <u>the</u><u> </u><u>Ball</u><u> </u><u>will</u><u> </u><u>hit </u><u>the</u><u> ground</u><u> </u><u>when</u><u> </u><u>the</u><u> height</u><u> is</u><u> </u><u>0</u>
- <u>solving</u><u> </u><u>quadratics </u><u>using</u><u> </u><u>quadratic</u><u> formula</u>
- <u>PEMDAS</u>
<h3>let's solve: </h3>













