Answer:
Mean, m = 72
Step-by-step explanation:
It is given that, Carl earned grades of 62, 78, 59, and 89 on four math tests.
It is required to find the mean of his grades.
Mean of a data is given by :
Sum of observations is 62 + 78 + 59 + 89 = 288
Total no of observations are 4
So, mean of his grades is :
So, the mean of his grades is 72.
Label the 3 distinct sides of the box. I arbitrarily chose the letters a, b and c.
Use the info about areas as follows:
ab=54 in^2
ac=90 in^2
bc=60 in^2
Here you have 3 equations in 3 unknowns (a, b and c), which is enough info to use to determine a, b and c. Then the volume of the box is a*b*c.
Example: bc = 90, but c = 60/b. You could subst. 60/b for c in the 2nd and 3rd equation, which will eliminate c completely and leave you with 2 equations in 2 unknowns.
Continuing this procedure, I determined that a=9, b=6 and c=10. Thus, the volume of the box is V = 9*6*10 = 540 cubic inches (answer)
Answer:
Step-by-step explanation:12y ×4 =21
48y=21
Y=0.44
Mark brainlest if correct pls
If the original price is 16, then 3/4 of 16 is 12.
$12
Dividing 16 by 4 (the denominator), you get 4. Then 4 x 3 (the numerator) is 12.
