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Klio2033 [76]
2 years ago
7

Evaluate the expression: 4(8 − 6)5 2 − 6 ÷ (−3).

Mathematics
1 answer:
mr Goodwill [35]2 years ago
7 0

Answer:

86 or 32, depending on the correctness of the syntax

Step-by-step explanation:

We use PEMDAS:

Parentheses: 4(2)5 2-6/(-3)

Exponents: <em>I'm assuming that all the syntax is correct (so no exponents).</em>

Multiplication and Division: 40*2+6 = 80 + 6

Addition and Subtraction: 86

If you copy+pasted this expression, then the original equation would have been: (4(8 − 6)^5)/(2 − 6 ÷ (−3)). We can use PEMDAS:

Parentheses: (4(2)^5)/(2 - 6 ÷ (−3))

  • We solve the parentheses individually using PEMDAS:
  • Exponents: (4*32) <-- Numerator | Denominator -->(2 - 6 ÷ (−3))
  • Multiplication and Division: 128 <-- Numerator | Denominator --> 2 + 2
  • Addition and Subtraction: 128 < -- Numerator | Denominator --> 4

We now have the following fraction: 128/4

That simplifies to 32

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<img src="https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7BW%7D%20%3D%202" id="TexFormula1" title="\sqrt[4]{W} = 2" alt="\sqrt[4]{W} = 2
solmaris [256]

Answer:

<h2>W = 16</h2>

Step-by-step explanation:

<h3>\sqrt[4]{W}  = 2 </h3>

To find W raise each of the sides of the equation to the power 4 to make W stand alone

That's

<h3>( { \sqrt[4]{W} })^{4}  =  {2}^{4}</h3>

We have

W = 2⁴

We have the final answer as

<h3>W = 16</h3>

Hope this helps you

6 0
3 years ago
P
Sindrei [870]

Answer:

where is the diagram

4 0
3 years ago
3/unknow ÷5=1/10<br> what in the unknown?
saul85 [17]
3/x<span>÷5=1/10
3</span><span>÷5=1/10*x
6/10=1/10*x
6=x</span>
5 0
3 years ago
Read 2 more answers
Find the zeros of the function f(x) = x2 + 5x + 6. A) y = 6 because the graph crosses the y-axis at 6. B) y = -0.25 because that
Fofino [41]

Answer:

D.)

Step-by-step explanation:

The zero's are referencing when y=0, note that when y=0 they are talking about the x-intercepts.  You can graph the function and see when the graph crosses the x-axis or solve for the x-values.  I will solve it via factoring and so:

f(x)=x^2+5x+6

Multiply the outer coefficients, in this case 1 and 6, and 1×6=6.  Now let's think about all the factors of 6 we have: 6×1 and 2×3.  Now is there a way that if we use any of these factors and add/subtract them they will return the middle term 5?  Actually we can say 6-1=5 and 2+3=5.  Let's try both.

First let's use 6 and -1 and so:

x^2+5x+6\\\\x^2+6x-x+6\\\\x(x+6)-1(x-6)

Notice how we have (x+6) and (x-6), these factors do not match so this is incorrect.

Now let's try 2 and 3 and so:

x^2+5x+6\\\\x^2+3x+2x+6\\\\x(x+3)+2(x+3)\\\\(x+2)(x+3)

Notice how the factors (x+3) matched up so this is a factor and so is (x+2), now to solve for the zero's let's make f(x)=0 and solve each factor separately:

Case 1:

f(x)=x+2\\\\0=x+2\\\\x=-2

Case 2:

f(x)=x+3\\\\0=x+3\\\\x=-3

So your zero's are when x=-2 and x=-3.

D.) x=-3 and x=-2 because the graph crosses the x-axis at -3 and -2.


~~~Brainliest Appreciated~~~

8 0
3 years ago
The points (1, 3) and (−3, 7) lie on a line. where does the line cross the x-axis?
Anastasy [175]
First, we find the equation of the line...

(1,3),(-3,7)
slope = (7 - 3) / (-3 - 1) = 4/-4 = -1

y = mx + b
slope(m) = -1
use either of ur points.... (1,3)...x = 1 and y = 3
now sub into the formula and find b, the y int
3 = -1(1) + b
3 = -1 + b
3 + 1 = b
4 = b
so the equation for this line is : y = -1x + 4 which is usually written as :
 y = -x + 4

Now...to find where the line crosses the x axis (or the x intercept)...we sub in 0 for y and solve for x

y = -x + 4
0 = -x + 4
x = 4... so ur x intercept (where the line crosses the x axis) is : (4,0)

3 0
3 years ago
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