Vcylinder-Vsphere=water
Vcylinder=hpir^2
Vsphere=(4/3)pir^3
given
cylinderradius=30 and h=100
Vcylinder=100pi30^2=100pi900=90000pi
let's leave it in terms of pi for more exactness
sphereradius=12
Vsphere=(4/3)pi12^3=2304pi
cylinder-sphere=90000pi-2304pi=87696pi
using pi=3.14
water=275365.44 cubic cm
last option is corrrect
12/25 is 48% becuase 12/25 is alao 48/100 because 12 x 4= 48 and 25 x 4= 100.
<span>N(t) = 16t ; Distance north of spot at time t for the liner.
W(t) = 14(t-1); Distance west of spot at time t for the tanker.
d(t) = sqrt(N(t)^2 + W(t)^2) ; Distance between both ships at time t.
Let's create a function to express the distance north of the spot that the luxury liner is at time t. We will use the value t as representing "the number of hours since 2 p.m." Since the liner was there at exactly 2 p.m. and is traveling 16 kph, the function is
N(t) = 16t
Now let's create the same function for how far west the tanker is from the spot. Since the tanker was there at 3 p.m. (t = 1 by the definition above), the function is slightly more complicated, and is
W(t) = 14(t-1)
The distance between the 2 ships is easy. Just use the pythagorean theorem. So
d(t) = sqrt(N(t)^2 + W(t)^2)
If you want the function for d() to be expanded, just substitute the other functions, so
d(t) = sqrt((16t)^2 + (14(t-1))^2)
d(t) = sqrt(256t^2 + (14t-14)^2)
d(t) = sqrt(256t^2 + (196t^2 - 392t + 196) )
d(t) = sqrt(452t^2 - 392t + 196)</span>
Answer:
6
Step-by-step explanation:
Answer:
the best equation would be A-99=n
Step-by-step explanation:
