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Maksim231197 [3]
3 years ago
11

What are the solutions of the equation c2-10c=0

Mathematics
2 answers:
MA_775_DIABLO [31]3 years ago
8 0
In this question, you are given an equation with one variable which is c. Then, it will be possible to find out the c value. Assuming the equation is c^2 - 10c = 0 then the calculation should be:

c^2 - 10c = 0 
(c) (c - 10) = 0 
c=0, c=10
Deffense [45]3 years ago
7 0
c=0,10 would be the best choice
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The manager of a snack bar buys bottled water in packs of 35 and candy bars in packs of 20. Then, she sells the items individual
Lerok [7]

\Huge\bf{\underline{\red \dag { Aиѕωєя }}} \red \dag

4 Packs of water and 7 Packs of candy bars.

So, we wanna know the smallest number that both 35 and 20 will go into.

Find the Least Common Multiple (LCM), but to find the LCM we need to find the prime factorization of each of the following number :-

\sf {35 = 5(7)}

\sf \red {20 = 5(4)}

\sf {4 = 2(2)}

\sf \red {20 = 5(2)(2)

~Now multiply all the numbers by 5 :-

\sf  \pink{5(7)(2)(2) = 35(2)(2) = 70(2) = 140}

This means she needs 140 bottles of water and 140 candybars.

Water is sold in packs of 35, this means that she needs :

\sf \orange{ \frac{140}{35}  = 4\: packs \: of \: water}

Candy bars are sold in packs of 20, this means she needs :

\sf \green{ \frac{140}{20}  = 7 \: packs \: of \: candy \: bars}

<u>___________________</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u>

6 0
3 years ago
X/5-2=x/2+3 solve for x
Makovka662 [10]
Solve for x:x/5 - 2 = x/2 + 3
Put each term in x/5 - 2 over the common denominator 5: x/5 - 2 = x/5 - (10)/5:x/5 - (10)/5 = x/2 + 3
x/5 - (10)/5 = (x - 10)/5:(x - 10)/5 = x/2 + 3
Put each term in x/2 + 3 over the common denominator 2: x/2 + 3 = x/2 + 6/2:(x - 10)/5 = x/2 + 6/2
x/2 + 6/2 = (x + 6)/2:(x - 10)/5 = (x + 6)/2
Multiply both sides by 10:(10 (x - 10))/5 = (10 (x + 6))/2
10/5 = (5×2)/5 = 2:2 (x - 10) = (10 (x + 6))/2
10/2 = (2×5)/2 = 5:2 (x - 10) = 5 (x + 6)
Expand out terms of the left hand side:2 x - 20 = 5 (x + 6)
Expand out terms of the right hand side:2 x - 20 = 5 x + 30
Subtract 5 x from both sides:(2 x - 5 x) - 20 = (5 x - 5 x) + 30
2 x - 5 x = -3 x:-3 x - 20 = (5 x - 5 x) + 30
5 x - 5 x = 0:-3 x - 20 = 30
Add 20 to both sides:(20 - 20) - 3 x = 20 + 30
20 - 20 = 0:-3 x = 30 + 20
30 + 20 = 50:-3 x = 50
Divide both sides of -3 x = 50 by -3:(-3 x)/(-3) = 50/(-3)
(-3)/(-3) = 1:x = 50/(-3)
Multiply numerator and denominator of 50/(-3) by -1:Answer:  x = (-50)/3
7 0
3 years ago
A box has 11 marbles, 3 of which are white and 8 of which are red. A sample of 4 marbles are selected randomly from the box with
aliina [53]

14/99

Select 1 marble; the chance that it is white is 4/12. Select a 2nd marble; the chance that it is white is 3/11. Select a 3rd; the chance it is white is 2/10. Select a 4th; the chance it is red is 8/9. Select a 5th; the chance it is red is 7/8. The chance of getting this specific set of 5 marbles in this order is (4/12)×(3/11)×(2/10)×(8/9)×(7/8)=(2×7)/(11×10×9).

This specific set could occur in the permutation of 5 things taken 5 at a time where 3 are identical (white), and the other 2 are also identical (red). The formula for this is 5!/(3!2!)=10.

Combining the chance of getting white, white, white, red, red with the number of ways 3 white and 2 red could have been distributed in the draw of 5 marbles gives the answer:

{(2×7)/(11×10×9)}×10=14/99

A similar process will show that the chance of getting 5 red marbles is 7/99; 4 white and 1 red is 1/99; 2 white and 3 red is 42/99; and 1 white and 4 red is 35/99.

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2 years ago
Function: f(x) = 2x + 1<br> It x = 0, what is the y output?
Maru [420]

Answer:

1

Step-by-step explanation:

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Daniel [21]

The answer is

10+x/6

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3 years ago
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