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qaws [65]
3 years ago
6

Below is the five-number summary for 136 hikers who recently completed the John Muir Trail (JMT). The variable is the amount of

time to complete the 212-mile hike from Yosemite Valley across the high Sierras to the top of Mount Whitney. Five-number summary: Minimum: 9 days Q1: 18 days Median: 21 days Q3: 28 days Maximum: 56 days If we use the 1.5 * IQR rule to determine whether there are any outliers, what is the right boundary?
Mathematics
1 answer:
Naddik [55]3 years ago
4 0

Answer:

43

Step-by-step explanation:

We have the following data:

Total number of hikers: 136

Minimum: 9 days

Q1 : 18 days

Median: 21 days

Q3: 28 days

Maximum: 56 days

Using the 1.5 Interquartile rule means:

Left boundary: Q1 - 1.5 × IQR

Right boundary: Q3 + 1.5 × IQR

We first calculate the IQR (Interquartile Range): Q3 - Q1

⇒ 28 - 18 = 10

Right boundary: 28 + 1.5 × 10

= 28 + 15

= 43

Hence the right boundary is 43.

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A coin is flipped eight times where each flip comes up either heads or tails. How many possible outcomes a) are there in total?
attashe74 [19]

Answer:

There are 256 ways in total.

There are 56 possible outcomes contain exactly three heads.

The possible outcomes contain at least three heads is 219.

The possible outcomes contain the same number of heads and tails are 70.

Step-by-step explanation:

Consider the provided information.

A coin is flipped eight times where each flip comes up either heads or tails.

Part (a) How many possible outcomes are there in total?

Each time we flip a coin it comes up either heads or tail.

Therefore the total number of ways are:

2\times 2\times 2\times 2\times 2\times 2\times 2\times 2=2^8=256

Hence, there are 256 ways in total.

Part (b) contain exactly three heads?

We want exactly 3 heads, therefore,

n=8 and r=3

According to the definition of combination: \binom{n}{r}=\frac{n!}{r!(n-r)!}

\binom{8}{3}=\frac{8!}{3!(5)!}=56

Hence, there are 56 possible outcomes contain exactly three heads.

Part (c) contain at least three heads?

For 3 heads: \binom{8}{3}=\frac{8!}{3!(5)!}=56

For 4 heads: \binom{8}{4}=\frac{8!}{4!(4)!}=70

For 5 heads: \binom{8}{5}=\frac{8!}{5!(3)!}=56

For 6 heads: \binom{8}{6}=\frac{8!}{6!(2)!}=28

For 7 heads: \binom{8}{7}=\frac{8!}{7!(1)!}=8

For 8 heads: \binom{8}{8}=1

Now add them as shown:

56+70+56+28+8+1=219

Hence, the possible outcomes contain at least three heads is 219.

Part (d) contain the same number of heads and tails?

Same number of heads and tails means that the value of r=4.

Therefore,

\binom{8}{4}=\frac{8!}{4!(4)!}=70

Hence, the possible outcomes contain the same number of heads and tails are 70.

6 0
3 years ago
How do you solve this answer
Dennis_Churaev [7]

Answer:

i think that the inquality is true but idk the solution..

Step-by-step explanation:

3 0
3 years ago
An average bathtub holds about 110,000 milliliters of water.
damaskus [11]
110 liters. 1000ml = 1 liter. Move the decimal 3 places to the left,so 110,000 ml becomes 110 liters.
6 0
3 years ago
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What is the solution to this equation 8 minus 7a equals negative 6a plus 9
densk [106]
8 - 7a = - 6a + 9
a = - 1

i am a mathematics teacher. if anything to ask please pm me
7 0
3 years ago
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HElp pleassssssss due in few mins
NeX [460]

Answer:

B) 4 cm

Step-by-step explanation:

Pentagon ABCDE is 1.75 times larger than Pentagon LMNOP. In Pentagon ABCDE, side AB is 7 cm. The side across of it (DE) is also 7. Side DE is Side OP on Pentagon LMNOP. To solve for it, divide 7/1.75 to get 4.

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