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deff fn [24]
3 years ago
6

Find two consecutive even integers

Mathematics
1 answer:
Fantom [35]3 years ago
8 0
You can set up a system of equations with x being the smaller number and y being the larger number. So the first equation would be 2y=5x-14 and the second equation would be x=y-2. You can solve by substitution and substitute y-2 into the x in the first equation to get 2y=5(y-2)-14. You can solve this out and it ends up simplifying to y=8. So you know the larger number is 8. So since the larger number is 8 and they are consecutive even integers, the smaller number must be 6. So the two numbers would be 6 and 8.
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3(1.5x+9)= tell me NOW
Misha Larkins [42]

Answer:

x = -6

Step-by-step explanation:

Simplifying

3(1.5x + 9) = 0

Reorder the terms:

3(9 + 1.5x) = 0

(9 * 3 + 1.5x * 3) = 0

(27 + 4.5x) = 0

Solving

27 + 4.5x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-27' to each side of the equation.

27 + -27 + 4.5x = 0 + -27

Combine like terms: 27 + -27 = 0

0 + 4.5x = 0 + -27

4.5x = 0 + -27

Combine like terms: 0 + -27 = -27

4.5x = -27

Divide each side by '4.5'.

x = -6

Simplifying

x = -6

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3 years ago
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