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Alika [10]
3 years ago
15

PLEASE HELP!!! How is the process for solving multiplication and division one-step equations like solving one-step addition and

subtraction equations?
Mathematics
1 answer:
777dan777 [17]3 years ago
8 0
All of these only require a single operation before you get x alone. for example:

x - 2 = 6
compared with
2x = 6

for the first one, you add two and get x = 8. for the second one, you divide by 2 and get x = 3. they're both a single step, as the name "one-step" equations tells you, and you only have to divide, multiply, add, or subtract one value.
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Larry bought 12 containers of pasta salad for a school picnic. Each container held the same number of ounces of salad. Students
tester [92]

Answer:

12 p - 8 p,  4p ( 3 - 2)

Step-by-step explanation:

p = equal the number of ounces of pasta salad in one container

then 12 × p = 12 p in 12 containers

the students finished the pasta salad in 8 containers which equals = 8 p

the number of ounces of pasta left = 12 p - 8 p  

b) using the distributive property for example a ( b + c) = ( a×b) + (a ×c)

12 p - 8 p = 4p ( 3 - 2)

6 0
3 years ago
A circular lid has a diameter of 12 inches. What is the exact area of the lid? A. 6π square inches B. 12π square inches C. 24π s
kaheart [24]
The area of any circle is equal to \pi r^2, where r is the radius.

We know that the diameter is 12. The radius is always half of the diameter, so the radius of our circle must be 6.

Substitute 6 for r in our equation and simplify.

π6² = π6×6 = 36π in²
6 0
4 years ago
Slove the equation <br> ×+20=29
photoshop1234 [79]

Answer: x = 9

Step-by-step explanation:

x + 20 = 29

x  = 9

9 + 20 = 29

8 0
4 years ago
What is the converse of ​r-&gt;(~q v p)
alexira [117]

Answer:

 r =>  (\neg q \ \lor p)  \ \equiv  \  q \ \land \ \neg p => \neg r

Step-by-step explanation:

In general, remember that the converse of    a => b       is     \neg b  =>   \neg a , therefore in this case  a = r   \ \ ,  b = \neg q \ \lor p

so   r =>  (\neg q \ \lor p)  \ \equiv  \  q \ \land \ \neg p => \neg r

   

8 0
3 years ago
How do you find the area of a right triangle if you only have the base
valentina_108 [34]

Step-by-step explanation:

You can find the area of a right triangle the same as you would any other triangle by using the following formula:

A = (1/2)bh, where A is the area of the triangle, b is the length of the base and h is the height of the triangle; However, with a right triangle, it's much more convenient in finding its area if we utilize the lengths of the two legs (the two sides that are shorter than the longest side, the hypotenuse and that are perpendicular to each other and thus form the right angle of the right triangle), that is, since the two legs of a right triangle are perpendicular to each other, when we treat one leg as the base, then, consequently, we can automatically treat the length of the other leg as the height, and if we initially know the lengths of both legs, then we can then just plug this information directly into the area formula for a triangle to find the area A of the right triangle.

For example: Find the area of a right triangle whose legs have lengths of 3 in. and 4 in.

Make the 4 in. leg the base. Since the two legs of a right triangle are perpendicular to each other, then the length of the other leg is automatically the height of the triangle; therefore, plugging this information into the formula for the area of a triangle, we have:

A = (1/2)bh

= (1/2)(4 in.)(3 in.)

= (1/2)(12 in.²)

A = 6 in.² (note: in.² means square inches)

8 0
3 years ago
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