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Kitty [74]
3 years ago
11

ASAP how did you get the answer (Will mark brianist)

Mathematics
1 answer:
Travka [436]3 years ago
6 0
The answer is A. None of the other answers would make sense and because choosing 10 from each classroom will provide a better result then the other two.
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Differences between 7 1/8 - 1 7/8
Mrrafil [7]
(7-1/8) - (1-7/8) = 57/8 -15/8 = 21/4
8 0
3 years ago
Read 2 more answers
Samantha sends her son, Barry, to a preschool center on certain days. The cost of preschool is $45 per day along with a fixed mo
Travka [436]

Answer: Option D

D. 880 = 45d + 70; 18\ days

Step-by-step explanation:

We know that the cost of preschool is $ 45 per day plus a monthly fee of $ 70.

We also know that a total of $ 880 was paid last month

To write an equation that represents this situation, let us call "d" the number of days that Barry attends school

So the cost was:

45d + 70 = 880

Now we solve the equation for the variable d

45d= 880-70

d= \frac{810}{45}

d= 18\ days

Therefore answer is the option D

8 0
3 years ago
What is the LCD of 4, 5, and 6
Ahat [919]
Solutions 

<span>To solve the problem our first step is to find the prime factorization of each number. </span>

4 = 2² 
<span>5 = 5 </span>
<span>6 = 2 x 3 
</span>
Calculations 

<span>LCM = 2² x 3 x 5 = 60 </span>
6 0
3 years ago
If x varies directly as y, and x = 7.5 when y = 10, find x when y = 4.
Lilit [14]
The answer is A) 3.
I hope this helps.
7 0
3 years ago
Read 2 more answers
Suppose that you are in charge of evaluating teacher performance at a large elementary school. One tool you have for this evalua
Strike441 [17]

Answer:

a) Standard error = 2

b) Range = (76.08, 83.92)

c) P=0.69

d) Smaller

e) Greater

Step-by-step explanation:

a) When we have a sample taken out of the population, the standard error of the mean is calculated as:

\sigma_m=\dfrac{\sigma}{\sqrt{n}}=\dfrac{10}{\sqrt{25}}=\dfrac{10}{5}=2

where n is te sample size (n=25) and σ is the population standard deviation (σ=10).

Then, the standard error of the classroom average score is 2.

b) The calculations for this range are the same that for the confidence interval, with the difference that we know the population mean.

The population standard deviation is know and is σ=10.

The population mean is M=80.

The sample size is N=25.

The standard error of the mean is σM=2.

The z-value for a 95% confidence interval is z=1.96.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_M=1.96 \cdot 2=3.92

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 80-3.92=76.08\\\\UL=M+t \cdot s_M = 80+3.92=83.92

The range that we expect the average classroom test score to fall 95% of the time is (76.08, 83.92).

c) We can calculate this by calculating the z-score of X=79.

z=\dfrac{X-\mu}{\sigma}=\dfrac{79-80}{2}=\dfrac{-1}{2}=-0.5

Then, the probability of getting a average score of 79 or higher is:

P(X>79)=P(z>-0.5)=0.69146

The approximate probability that a classroom will have an average test score of 79 or higher is 0.69.

d) If the sample is smaller, the standard error is bigger (as the square root of the sample size is in the denominator), so the spread of the probability distribution is more. This results then in a smaller probability for any range.

e) If the population standard deviation is smaller, the standard error for the sample (the classroom) become smaller too. This means that the values are more concentrated around the mean (less spread). This results in a higher probability for every range that include the mean.

6 0
3 years ago
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