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SashulF [63]
2 years ago
10

3\sqrt{3} )^{2} +5^{2}" alt="\sqrt({3\sqrt{3} )^{2} +5^{2}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Triss [41]2 years ago
8 0

Answer:

<u>2√13</u>

Step-by-step explanation:

⇒ √(3√3)² + 5²

⇒ √27 + 25

⇒ √52

⇒ <u>2√13</u>

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Change 33/4 to a mixed number
BaLLatris [955]

Answer:

Step-by-step explanation:

33/4 already reduced (simplified) Improper fraction, rewrite it as a mixed number: 33 ÷ 4 = 8 and remainder = 1 => 33/4 = (8 × 4 + 1)/4 = 8 + 1/4 = 8 1/4

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3 years ago
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Which steps could be used to solve this story problem? PLEASE HELP ULL GET MARK BRAINLIEST IF U ANSWER IT FIRST PLZZ AND 7 PTS P
Fiesta28 [93]
The answer would be C.
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4 years ago
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Select the indicated real n th root(s) of a. n=5 a=243
Anastaziya [24]

Answer:

Ask your teacher because i don't know how to do it or i would help sorry

Step-by-step explanation:

6 0
3 years ago
Workers are grouped by their areas of expertise and are placed on at least one team. 20 are on the marketing team, 30 are on the
liubo4ka [24]

Answer: C. 74

Step-by-step explanation:

Let M= Number of workers are in marketing team .

S = Number of workers are in Sales team.

V = Number of workers are in Vision team.

As per given , we have

n(M) = 20 , n(S) = 30 , n(V) = 40

n(M∩S) = 5  ,  n(V∩S) = 6  ,  n(M∩V)  = 9

n(M∩S∩V) =4

Using formula of sets , we get

n(M∪S∪V) =n(M)+n(S) +n(V) -n(M∩S) - n(V∩S)-n(M∩V) +n(M∩S∩V)

Substitute the corresponding values , we get

n(M∪S∪V) =20+30+40-5-6-9 +4

=  74

∴ The number of workers are in at least one team = 74

Therefore , the total number of workers =74

Hence, the correct option is : C. 74

7 0
4 years ago
How many ways can you make change for a $50 bill using $5, $10, and $20 bills?
aleksley [76]

Answer:

There are 12 ways to make change for a $50 bill using $5, $10 and $20 bills

Step-by-step explanation:

Let's write down every possibility starting by using the largest quantity of $20 bills and we'll go from there, everytime that we get a $10 bill we will split it in the next option into 2 $5 bills.

(20)(20)(10)

(20)(20)(5)(5)

(20) (10)(10)(10)

(20)(10)(10)(5)(5)

(20)(10)(5)(5)(5)(5)

(20)(5)(5)(5)(5)(5)(5)

Now we start with the largest quantity of $10 bills (5) and go from there, splitting them into two 5 dollar bills in the next option.

(10)(10)(10)(10)(10)

(10)(10)(10)(10)(5)(5)

(10)(10)(10)(5)(5)(5)(5)

(10)(10)(5)(5)(5)(5)(5)(5)

(10)(5)(5)(5)(5)(5)(5)(5)(5)

(5)(5)(5)(5)(5)(5)(5)(5)(5)(5)

3 0
3 years ago
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