<img src="https://tex.z-dn.net/?f=%5Csqrt%28%7B3%5Csqrt%7B3%7D%20%29%5E%7B2%7D%20%2B5%5E%7B2%7D" id="TexFormula1" title="\sqrt({

All categories

SashulF [63]

1 year ago

3\sqrt{3} )^{2} +5^{2}" alt="\sqrt({3\sqrt{3} )^{2} +5^{2}" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

Triss [41]1 year ago

8 0

Answer:

Step-by-step explanation:

⇒ √(3√3)² + 5²

⇒ √27 + 25

⇒ √52

⇒ <u>2√13</u>

You might be interested in

Which of the following statements are true?

Eduardwww [97]

Answer:

B, C

Step-by-step explanation:

Consider all options:

A. The graph of the function $f(x)=\dfrac{1}{2}\sqrt[3]{x}$ is vertically shrunk by a factor $\frac{1}{2}$ the graph of the function $f(x)=\sqrt[3]{x},$ so the domain and the range of both functions are the same. This option is false.

B. The graph of the function $f(x)=\dfrac{1}{2}\sqrt[3]{x}$ is vertically shrunk by a factor $\frac{1}{2}$ the graph of the function $f(x)=\sqrt[3]{x},$ so the domain and the range of both functions are the same. This option is true.

C. The graph of the function $f(x)=\dfrac{1}{2}\sqrt[3]{(x-2)}$ is translated 2 units to the right and vertically shrunk by a factor $\frac{1}{2}$ the graph of the function $f(x)=\sqrt[3]{x},$ so their graphs are similar except the first graph is shifted right and shrunk vertically by a factor of $\frac{1}{2}.$ . This option is true.

D. The function $f(x)=\dfrac{1}{2}\sqrt{x}$ has the domain and the range all non-negative real values. The function $f(x)=\sqrt[3]{x}$ has the domain and the range all real values. So this option is false.