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zhuklara [117]
3 years ago
8

#1. Ethylene glycol (antifreeze) has a density of 1.11 g/cm^3. 1/What is the mass in grams of 385mL of this liquid? 2/What is th

e volume in liters of 3.43 kg of this liquid?#2. What is the volume in liters of 3.43 kg of this liquid? density of 1.11 g/cm^3. M/D=V Plug in info (3.43 kg) / (1.11 g/cm^3)=V
Chemistry
1 answer:
Svetradugi [14.3K]3 years ago
4 0
Density is equal to mass over volume occupied of an object. Given the density of the liquid which is 1.11 g/ml. To get the mass of the liquid given also the volume, we substitute: mass= volume * density. Hence in 1) the mass is 427.35 ml. In 2) the given is equivalent to 3430 g. Hence, the volume asked in 2) is 3090.09 ml.
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Of the following, which is most likely to result after a farmer sprays his crops with pesticides?D. A neighbor’s well tests positive for pesticides. 

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4 years ago
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What is the mass percent concentration of a solution containing 29.0 g NaCl and 115.0 mL of water? Assume a density of 1.00 g/mL
marin [14]

Answer:

Mass percent concentration: 25,2% m/m

Explanation:

The percentage mass by mass indicates the grams of solute in 100 grams of solution. We convert the ml of water into g from the density formula:

δ= m/v    m=δx v= 1 g/ml x 115 ml= 115 g

115g solution-----29 g NaCl

100g solution----x=(100g solutionx29 g NaCl)/115g solution

x=25,2173913 g NaCl

5 0
3 years ago
Help asap please. Will mark as the brainliest... NO LINKS!!!
Ivan

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5 0
3 years ago
A mixture formed of isopropyl alcohol C,H,OH (70%) and water (30%), if you know
scZoUnD [109]

Answer:

(1) <em>C</em> C3H7OH = 9.200 M

(2) <em>C</em> C3H7OH = 11.647 m

Explanation:

mixture:

∴ 70% = (g C3H7OH/g mix)×100

∴ 30% = (gH2O/g mix)×100

∴ δ mix = 0.79 g/mL

assuming:

  • g mix = 100g = 0.100 Kg

⇒ V mix = (100g)×(mL/0.79g) = 126.582 mL mix = 0.1266 L mix

⇒ g C3H7OH = 70g

⇒ g H2O = 30g

∴ Mw C3H7OH = 60.1 g/mol

∴ Mw H2O = 18 g/mol

(1) Molar concentration (M):

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⇒ <em>C</em> C3H7OH = ((70 g)(mol/60.1 g))/(0.1266L) = 9.200 M

(2) molal concentration (m):

  • m ≡ mol solute/Kg mix

⇒ <em>C </em>C3H7OH = ((70 g)(mol/60.1g))/(0.100 Kg) = 11.647 m

7 0
4 years ago
Correct?
erica [24]
Correct answer is C

Na2O + H2O ----> 2 NaOH

:-) ;-)
4 0
4 years ago
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