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Effectus [21]
3 years ago
6

A mixture formed of isopropyl alcohol C,H,OH (70%) and water (30%), if you know

Chemistry
1 answer:
scZoUnD [109]3 years ago
7 0

Answer:

(1) <em>C</em> C3H7OH = 9.200 M

(2) <em>C</em> C3H7OH = 11.647 m

Explanation:

mixture:

∴ 70% = (g C3H7OH/g mix)×100

∴ 30% = (gH2O/g mix)×100

∴ δ mix = 0.79 g/mL

assuming:

  • g mix = 100g = 0.100 Kg

⇒ V mix = (100g)×(mL/0.79g) = 126.582 mL mix = 0.1266 L mix

⇒ g C3H7OH = 70g

⇒ g H2O = 30g

∴ Mw C3H7OH = 60.1 g/mol

∴ Mw H2O = 18 g/mol

(1) Molar concentration (M):

  • M ≡ mol solute/L mix

⇒ <em>C</em> C3H7OH = ((70 g)(mol/60.1 g))/(0.1266L) = 9.200 M

(2) molal concentration (m):

  • m ≡ mol solute/Kg mix

⇒ <em>C </em>C3H7OH = ((70 g)(mol/60.1g))/(0.100 Kg) = 11.647 m

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