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blsea [12.9K]
3 years ago
15

If a gas at a pressure of 600 mmHg and a volume of 200 mL is changed to 780 mmHg, then what will be the new volume?

Chemistry
1 answer:
svlad2 [7]3 years ago
8 0
P1V1=P2V2
(600/760)(.200)=(780/760)x
x=.1538L or 153.8mL
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If you are given only the mass number of neutrons, how do we find an atomic number?
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Mass number is the sum of protons and neutrons.

Atomic number is the total number of protons present.

Mass number = protons + neutrons

Atomic number = protons present.

From the above equations we can conclude that,

Atomic number= Mass number- neutrons.

Thus we can find out the atomic number by subtracting the number of neutrons from the mass number.

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Which of these is a mixture? a.water b.sugar c.carbon dioxide d.popcorn and salt​
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How did scientists find out about atoms before technology?
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When 6.040 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 18.95 grams of CO2 and 7.759 grams of H
algol [13]

Answer: The empirical formula is CH_2 and molecular formula is C_4H_8

Explanation:

We are given:

Mass of CO_2 = 18.95 g

Mass of H_2O= 7.759 g

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 18.59 g of carbon dioxide, =\frac{12}{44}\times 18.59=5.07g of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 7.759 g of water, =\frac{2}{18}\times 7.759=0.862g of hydrogen will be contained.

Mass of C = 5.07 g

Mass of H = 0.862 g

Step 1 : convert given masses into moles.

Moles of C =\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{5.07g}{12g/mole}=0.422moles

Moles of H=\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.862g}{1g/mole}=0.862moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C =\frac{0.422}{0.422}=1

For H =\frac{0.862}{0.422}=2

The ratio of C : H = 1: 2

Hence the empirical formula is CH_2.

The empirical weight of CH_2 = 1(12)+2(1)= 14 g.

The molecular weight = 56.1 g/mole

Now we have to calculate the molecular formula.

n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{56.1}{14}=4

The molecular formula will be=4\times CH_2=C_4H_8

6 0
3 years ago
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