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emmasim [6.3K]
3 years ago
12

Simplify each expression. Use positive exponents. A^4b^-3 ab^-2

Mathematics
2 answers:
Leni [432]3 years ago
8 0
\dfrac{a^4b^{-3}}{ab ^{-2}}=\dfrac{a^4}{a^1}\cdot\dfrac{b^{-3}}{b^{-2}}=a^{4-1}\cdot b^{-3-(-2)}=a^3\cdot b^{-3+2}=a^3\cdot b^{-1}=a^3\cdot\dfrac{1}{b}=\\\\\\=\boxed{\dfrac{a^3}{b}}
choli [55]3 years ago
6 0
\dfrac{a^4b^{-3}}{ab^{-2}}

= {a^{4-1}b^{-3+2}}

= {a^{3}b^{-1}}

= \dfrac{a^3}{b}


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7 0
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Read 2 more answers
I need help on this please
Paha777 [63]
When it's laid out like that. 2 division statements on either side with one unknown variable you just cross multiply really easy

5 x 24 / 6 = 20

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4 0
3 years ago
at which angles are the x and y coordinate on the unit circle exactly the same? give your answer in radians and degrees
MrMuchimi

Answer:

In radian :

\frac{\pi }{4} \ \text{and}\  \frac{5\pi }{4}

In degree :

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Step-by-step explanation:

the x and y coordinate on the unit circle exactly the same at the angles :

In radian :

\frac{\pi }{4} \ \text{and}\  \frac{5\pi }{4}

In degree :

45° and 225°

At those angles :

\left( x,y\right)  =\left( \frac{\sqrt{2} }{2} ,\frac{\sqrt{2} }{2} \right)  \ or\ \left( x,y\right)  =\left( -\frac{\sqrt{2} }{2} ,-\frac{\sqrt{2} }{2} \right)

7 0
2 years ago
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6 0
3 years ago
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