Answer:
No, This is not a valid Probability Distribution
Step-by-step explanation:
Probability [Neighbour walks with Beagle] = 20%
Probability [Neighbour walks with Golden Retriever] = 70%
Probability [Neighbour walks alone] = 30%
Disjoint Events are the events that have zero probability of occurring together. If all the three above items are disjoint, it means that it can never happen that two of them happen together.
The total (summed) probability of a valid probability distribution, with disjoint sets = 1 . In given case, total probability = 0.2 + 0.7 + 0.3 = 1.2 ; i.e > 1.
So, this probability distribution with stated disjoint events is not a Valid Probability distribution.
Answer:
0.7026
Step-by-step explanation:
Let X denote the lifetime of light bulb. Given where the mean is .
Recall that,
68 students* (25/100)= 17 students.
There are 17 students who had perfect attendance for the nine weeks~
Tan ( a + b ) = [ tan a + tan b ] / [ 1 - (tan a)*(tan b) ];
let be a = 2x and b = x;
=> tan 3x = [ tan 2x + tan x ] / [ 1 - (tan 2x)*(tan x) ] => (tan 3x)*[ 1 - (tan 2x)*(tan x) ] =
tan 2x + tan x => tan3x - tan 3xtan 2xtanx = tan 2x + tan x => <span> tan 3x−tan 2x−tanx = tan 3xtan 2xtanx.</span><span />