Step-by-step explanation:
(5√2-4√3)(5√2-4√3)=
(5√2-4√3)^2=(5√2)^2+(4√3)^2-2(5√2)(4√3)
=25*2+16*3-10√2*4√3
=50+48-10√2*4√3
=98-10√2*4√3 is the answer
So, you had done everything right so far (other than squaring the 2), but that was only half of the question.
to find the least common multiple, you need to first figure out what the prime factors have in common.

each have two twos. both have one 5, so we know our answer will look something like

now to figure out the other stuff... we have to represent the greatest amount of everything that is left, and we have 3s and 7s left over, so we need to figure out how many of each we need.
one has one 3 and one has two, so we need two threes. now our equation is

what's the only number we have to deal with? 7...
how many sevens does 60 have? 0, and 630 has 1, so we know we need one 7. our answer becomes
Answer:
hypotenuse:15
Step-by-step explanation:
Pythagorean Theorem is a^2 + b^2 = c^2
"a" and "b" are the legs, "c" is the hypotenuse
9^2 + 12^2 = 225
hypotenuse = 15
A Cube, has all equal sides, namely, the length, width and height
are all equal to each other
so.. notice the picture added here
you have really, 6 squares, stacked up to each other at the edges
so...what is the Area of one of those squares?
well, if the sides are equal, let's say the side is "x" long, then
the Area is

well, you have 6 of those squares, thus

solve for "x", to get one side's length