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TEA [102]
1 year ago
6

One leg of a triangle is 7 inches. another leg measures 5 inches. if the perimeter of the triangle is 19 inches, find the length

of the other side.

Mathematics
1 answer:
Setler79 [48]1 year ago
6 0

SOLUTION

A triangle has three sides. The sides of this triangle are 7 inches, 5inches and the unknown side.

Let the unknown side be x inches.

Perimeter is distance around a plane shape.

The perimeter of this triangle is 19,

\begin{gathered} \text{  That is the perimeter  1}9=7+5+x \\ 19\text{ = 12 }+x \\ x\text{ = 19 - 12 } \\ x\text{ = 7 inches } \end{gathered}

Therefore, the other side is 7 inches

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I need these 2 questions answered fast please.​
shtirl [24]

Answer:

75 ft / none of these (43)

Step-by-step explanation:

formula: (area =1/2bh)

so you take base × height and then take half of that number (divide by 2)

5 0
3 years ago
32 is 40% of what is the answer
ANTONII [103]
32 is 40% of?

32/40

32 ÷ 40 = 0.8
0.8 × 100 = 80
80

32 is 40% of 80. 
6 0
3 years ago
The shark are fed three times a day during the morning feeding 2/15 of a ton. During the afternoon feeding the weight of fish fe
UNO [17]

Answer:

The shark are fed \frac16 \ ton of fish during the night.

Step-by-step explanation:

Given:

Weight of fish fed in the morning = \frac{2}{15}\ ton

Also Given:

During the afternoon feeding the weight of fish fed will be 1/15 of a ton more than the fish fed during the morning.

Weight of fish fed in the afternoon = \frac{2}{15}+\frac{1}{15}=\frac{2+1}{15}=\frac{3}{15}\ ton

Total fish fed in whole day = \frac12 \ ton

We need to find the Weight of fish fed in the night.

Solution:

Now we can say that;

Weight of fish fed in the night can be calculated by by subtracting Weight of fish fed in the morning and Weight of fish fed in the afternoon from Total fish fed in whole day .

framing in equation form we get;

Weight of fish fed in the night = \frac{1}{2}-\frac{2}{15}-\frac{3}{15}= \frac{1}{2}-(\frac{2}{15}+\frac{3}{15})=\frac{1}{2}-\frac{2+3}{15}= \frac{1}{2}-\frac{5}{15} = \frac{1}{2}-\frac{1}{3}

Now we will use LCM for making the denominator common we get;

Weight of fish fed in the night = \frac{1\times3}{2\times3}-\frac{1\times2}{3\times2} = \frac{3}{6}-\frac{2}{6}

Now denominator are common so we will solve the numerators.

Weight of fish fed in the night = \frac{3-2}{6}=\frac16 \ ton

Hence The shark are fed \frac16 \ ton of fish during the night.

3 0
3 years ago
Consider the random experiment of tossing 3 fair coins and observing how many of them come to rest with the heads side of the co
zaharov [31]

Answer:

b. S = AUB

Step-by-step explanation:

Since the coins are tossed  3 times and each coin has head, H and tail, T(2 sides), the sample space is S = 2 × 2 × 2 = 2³ = 8

All the possible outcomes are HTT, HHT, HHH, THH, TTH, HTH,THT and TTT

Since S denote the sample space

S = {HTT, HHT, HHH, THH, TTH, HTH,THT, TTT}

Since A denote the event that at least 1 of the coins comes to rest with its heads side upwards, the possible outcomes are HTT, HHT, HHH, THH, TTH, HTH and THT

So, A = {HTT, HHT, HHH, THH, TTH, HTH,THT}

Also B denote the event that none of the coins comes to rest with its heads side upwards, that is no heads. The possible outcome is TTT

So, B = {TTT}

Since S denote the sample space

S = {HTT, HHT, HHH, THH, TTH, HTH,THT, TTT}

So, A ∪ B = {HTT, HHT, HHH, THH, TTH, HTH,THT} ∪  {TTT} = {HTT, HHT, HHH, THH, TTH, HTH,THT, TTT} = S

So, S = A ∪ B

So, S = A ∪ B does not denote an abuse of notation.

The answer is b.

7 0
3 years ago
What is 69 x 420 <br> Can you sub to me please?
Alex17521 [72]

Answer:

69x420=28,980

Step-by-step explanation:

i will

6 0
3 years ago
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