Help please.. find the area of the region that lies inside both curves

I need help with question 42. Can someone help me?

LiRa [457]

The answer is C and brainliest answer please.

5 0

3 years ago

Read 2 more answers

PLEASE HELP ASAP 35 PTS + BRAINLIEST TO RIGHT/BEST ANSWER

Semenov [28]

Answer:

(5,2,2)

Step-by-step explanation:

-3x+4y+2z = -3

2x-4y-z=0

y = 3x-13

Multiply the second equation by 2

2*(2x-4y-z)=0*2

4x -8y -2z =0

Add this to the first equation to eliminate z

-3x+4y+2z = -3

4x -8y -2z =0

-------------------------

x -4y = -3

Take the third equation and substitute it in for y

x - 4(3x-13) = -3

Distribute the 4

x - 12x +52 = -3

Combine like terms

-11x +52 = -3

Subtract 52 from each side

-11x +52-52 = -3-52

-11x = -55

Divide by -11

-11x/-11 = -55/-11

x=5

Now we can solve for y

y =3x-13

y =3*5 -13

y = 15-13

y=2

Now we need to find z

2x-4y-z=0

2(5) -4(2) -z=0

10-8 -z=0

2-z=0

Add z to each side

2-z+z= 0+z

2=z

x=5, y=2, z=2

(5,2,2)

3 0

3 years ago

PLZ CHECK MY ANSWER. Round your answer to the nearest tenth.

Umnica [9.8K]

Answer:

D. $70.34 cm^2$

Step-by-step explanation:

Area of sector of a circle is given as θ/360*πr²

Where,

r = radius = 12 cm

θ = 56°

Use 3.14 as π

Plug in the values into the formula and solve

$area = \frac{56}{360}*3.14*12^2$

$area = 70.34$

Area of the sector ABC = $70.34 cm^2$

The answer is D

4 0

3 years ago

35 POINTS AVAILABLE

aliina [53]

Answer:

Part 1) The length of each side of square AQUA is $3.54\ cm$

Part 2) The area of the shaded region is $(486\pi-648)\ units^{2}$

Step-by-step explanation:

Part 1)

step 1

Find the radius of the circle S

The area of the circle is equal to

$A=\pi r^{2}$

we have

$A=25\pi\ cm^{2}$

substitute in the formula and solve for r

$25\pi=\pi r^{2}$

simplify

$25=r^{2}$

$r=5\ cm$

step 2

Find the length of each side of square SQUA

In the square SQUA

we have that

SQ=QU=UA=AS

$SU=r=5\ cm$

Let

x------> the length side of the square

Applying the Pythagoras Theorem

$5^{2}=x^{2} +x^{2}$

$5^{2}=2x^{2}$

$x^{2}=\frac{25}{2}\\ \\x=\sqrt{\frac{25}{2}}\ cm\\ \\ x=3.54\ cm$

Part 2) we know that

The area of the shaded region is equal to the area of the larger circle minus the area of the square plus the area of the smaller circle

Find the area of the larger circle

The area of the circle is equal to

$A=\pi r^{2}$

we have

$r=AB=18\ units$

substitute in the formula

$A=\pi (18)^{2}=324\pi\ units^{2}$

step 2

Find the length of each side of square BCDE

we have that

$AB=18\ units$

The diagonal DB is equal to

$DB=(2)18=36\ units$

Let

x------> the length side of the square BCDE

Applying the Pythagoras Theorem

$36^{2}=x^{2} +x^{2}$

$1,296=2x^{2}$

$648=x^{2}$

$x=\sqrt{648}\ units$

step 3

Find the area of the square BCDE

The area of the square is

$A=(\sqrt{648})^{2}=648\ units^{2}$

step 4

Find the area of the smaller circle

The area of the circle is equal to

$A=\pi r^{2}$

we have

$r=(\sqrt{648})/2\ units$

substitute in the formula

$A=\pi ((\sqrt{648})/2)^{2}=162\pi\ units^{2}$

step 5

Find the area of the shaded region

$324\pi\ units^{2}-648\ units^{2}+162\pi\ units^{2}=(486\pi-648)\ units^{2}$

7 0

3 years ago

Select the correct answer.

Katena32 [7]

Answer:C consumer price index

Step-by-step explanation:

7 0

3 years ago