B Phytoplankton - Zooplankton - Arctic cod - Ringed sal
Explanation:
The food chain that describes the path through which energy takes will be phytoplankton-zooplankton-Arctic cod-Ringed sal. Energy moves in the ecosystem from producers to primary consumers then secondary and tertiary consumers.
- Autotrophs are those organisms that manufacture their own food. The use chemical substances from the environment to produce their nourishment which serves as the source of energy for the whole ecosystem too.
- Autotrophs are the producers in any ecosystem and they are usually the plants.
- The phytoplankton is an autotroph.
- Next up are the primary consumers that takes up the produced food by the autotrophs for their own nourishment. In the chain above, the Zooplankton is the primary consumer.
- The secondary consumer that feeds on the zooplankton is the Arctic cod.
- The tertiary consumer is the Ringed Sal which feeds directly on the Arctic cod.
Learn more:
food chain brainly.com/question/2497487
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The atoms of chlorine are held together by non-polar covalent bonds. Covalent bonds are formed between two or more atoms having zero or very small electronegativity difference. For homonuclear molecules where the two bonding atom are of the same kind, the electronegativity difference is zero.
This is done by reducing each number by a common factor for each formula.
C3H6O6- all can be divided by 3 -> CH3O3 (you don't have to put a 1 for C, only if your teacher requests it. It is generally understood if not written)
H2O2- all can be divided by 2 -> H1O1 (had to put the 1's bc of the unintended language)
C8H8S2- all can be divided by 2 -> C4H4S
P5O15- all can be divided by 5- PO3
*****it is important to note that <em>all </em>numbers in the molecular formula are divided by the same thing to reduce them. decimals are <em>never </em>used in empirical formulas, only whole numbers.*****
The mole fraction of cation (Al)=0.4
<h3>Further explanation</h3>
Given
1 M of Aluminium sulphate
Required
The mole fraction of cation
Solution
Ionization of the Aluminum sulfate solution( assume 1 L solution ) :
mol Al₂(SO₄)₃ = M x V = 1 M x 1 L = 1 mol
Al₂(SO₄)₃⇒2Al³⁺ + 3SO₄²⁻
1 mol 2 mol 3 mol
From this equation, total mol in solution = 2+3 = 5 moles
Mol fraction Al(as a cation) :
= 2/5=0.4