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Basile [38]
3 years ago
14

Which of the following would shift the following equilibrium system to the right? C2H2(g) + H2O(g) ⇌ CH3CHO(g) Removing H2O(g) f

rom the system Adding CH3CHO(g) to the system Removing C2H2(g) from the system Adding H2O(g) to the system
Chemistry
2 answers:
sergey [27]3 years ago
4 0
<h2>Answer:</h2>

<u>The right choice is </u><u>Adding H2O(g) to the system</u>

<h2>Explanation:</h2>

If we dilute a solution by adding solvent like water, all of the concentrations will decrease and a change in Q occurs. If there are more species in solution that are products than reactants then Q will decrease. Hence the reaction will then shift towards the right side which is product side to reach equilibrium because there will be an increase the concentration of the reactants side.

Fittoniya [83]3 years ago
3 0

Answer:

Adding H₂O(g) to the system.

Explanation:

  • Le Châtelier's principle states that when there is an dynamic equilibrium, and this equilibrium is disturbed by an external factor, the equilibrium will be shifted in the direction that can cancel the effect of the external factor to reattain the equilibrium.

<u><em>1) Removing H₂O(g) from the system:</em></u>

  • This will decrease the concentration of the reactants side, so the reaction will be shifted to the left side to suppress the removal of H₂O(g) from the system.

<u><em>2) Adding CH₃CHO(g) to the system :</em></u>

  • This will increase the concentration of the products side, so the reaction will be shifted to the left side to suppress the adding CH₃CHO(g) to the system.

<u><em>3) Removing C₂H₂(g) from the system:</em></u>

  • This will decrease the concentration of the reactants side, so the reaction will be shifted to the left side to suppress the removal of C₂H₂(g) from the system.

<u><em>4) Adding H₂O(g) to the system:</em></u>

  • This will increase the concentration of the reactants side, so the reaction will be shifted to the right side to suppress the addition of H₂O(g) to the system.
  • <u><em>So, it is the right choice.</em></u>
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Chlorine has two naturally stable isotopes: 35Cl (34.968853 amu) and 37Cl (36.965903 amu). The natural abundance of each isotope
allochka39001 [22]

Answer:

35Cl ⇒ 34.968853 amu  has an abundance of 30.05%

Explanation:

The molar mass of chlorine, (which is the average of all its naturally stable isotope masses), is 36.36575 amu.

There are 2 naturally stable isotopes, this means together they have an abundance of 100%

The isotopes are:

35Cl ⇒ 34.968853 amu  has an abundance of X %

37Cl ⇒ 36.965903 amu  has an abundance of Y %

X + Y = 100%   OR X = 100% - Y

36.36575 = 34.968853X + 36.965903Y  

36.36575 = 34.968853(1-Y) + 36.936.96590365903Y

36.36575 = 34.968853 -34.968853Y + 36.965903Y

1.396897 = 1.99705Y

Y = 0.699 = 69.95%

X = 100-69.9 = 30.05%

To control, we can plug in the following equation:

34.968853 * 0.3005 + 36.965903 * 0.6995 = 36.3658

This means

37Cl ⇒ 36.965903 amu  has an abundance of 69.95 %

35Cl ⇒ 34.968853 amu  has an abundance of 30.05%

7 0
3 years ago
Which definition best describes a titration?
Juliette [100K]

Answer:

the answer is C

Explanation:

4 0
3 years ago
Read 2 more answers
A solution is prepared by adding 0.0231moles of H3O+ ions to 3.33L of water. What is the pH of this solution
MrMuchimi

Answer:

2.15

Explanation:

For this question, we have to remember the <u>pH formula</u>:

pH~=~-Log[H_3O^+]

By definition, the pH value is calculated when we do the -Log of the concentration of the <u>hydronium ions</u> (H_3O^+). So, the next step is the calculation of the <u>concentration</u> of the hydronium ions. For this, we have to use the <u>molarity formula</u>:

M=\frac{mol}{L}

We already know the number of moles (0.0231 moles) and the volume (3.33 L). So, we can plug the values into the molarity formula:

M=\frac{0.0231~moles}{3.33~L}=0.00693~M

With this value, now we can calculate the pH value:

pH~=~-Log[0.00693~M]~=~2.15

<u>The pH would be 2.15</u>

I hope it helps!

8 0
3 years ago
Acetone is the main chemical in nail polish and has a density of 0.7857 g/mL. What is the volume of 6.54g of acetone ?
trapecia [35]

8.3mL

Explanation:

Given parameters:

Mass of acetone = 6.54g

Density of acetone = 0.7857 g/mL

Unknown:

Volume of acetone = ?

Solution:

Density is defined as the mass per unit volume of a substance. It is expressed mathematically as shown below:

  Density = \frac{Mass}{Volume}

Since the unknown is volume, we make it the subject of the formula

Volume =  \frac{mass}{density}

Input the values;

  Volume = \frac{6.54}{0.7857} = 8.3mL

learn more:

Volume brainly.com/question/2690299

#learnwithBrainly

5 0
3 years ago
Balancing equations<br> I'll give brainliest.
wel

Answer:

You should follow these steps:

Count each type of atom in reactants and products.

Place coefficients, as needed, in front of the symbols or formulas to increase the number of atoms or molecules of the substances.

Repeat steps 1 and 2 until the equation is balanced.

Explanation:

7 0
2 years ago
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