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2 years ago

12

Let f be a function defined on the closed interval -3 on what intervals, if any, is f increasing

1 answer:

Ann [662]2 years ago

8 0

No, it's a decreasing function

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Please help me asap

STALIN [3.7K]

7 1/10 is the answer bc you have the plain 7 and .1 is 1/10

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3 years ago

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Given b (x) = StartAbsoluteValue x + 4 EndAbsoluteValue, what is b (negative 10)?

dmitriy555 [2]

Answer:

The answer is 6

Step-by-step explanation:

b(x) = |x+4|

b(-10) = |-10+4|

= |-6| (absolute value is always interested in +ve value)

= 6

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2 years ago

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What is the value of -2 176 - 11/4 + 1 3/4? *

Helen [10]

Answer:-4351/2

Step-by-step explanation:

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2 years ago

FLVS Question 12 4.10 part two

LUCKY_DIMON [66]

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2 years ago

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Find an equation of the tangent to the curve at the given point by both eliminating the parameter and without eliminating the pa

jek_recluse [69]

Answer:2x-y=5

Step-by-step explanation:

Given

$x=6+\ln t$

$y=t^{2}+6$

$\left ( a\right )$ without eliminating parameter

$\frac{\mathrm{d} x}{\mathrm{d} t}$ = $\frac{1}{t}$

$\frac{\mathrm{d} y}{\mathrm{d} t}$ =2t

$\frac{\mathrm{d} y}{\mathrm{d} x}=2t^2$

at $\left ( 6,7\right )$

6=6+ $\ln\left ( t\right )$

t=1

Equation of line is given by

2= $\frac{y-7}{x-6}$

2x-12=y-7

2x-y=5

$\left ( b\right )$ by eliminating parameter

$x-6=\ln \left ( t\right )$

$t=e^{x-6}$

$y=t^2 +6$

$y=e^{\left ( 2x-12\right )}+6$

differentiating we get

$\frac{\mathrm{d}y}{\mathrm{d} x}=2e^\left ( 2x-12\right )$

$at \left ( 6,7\right )$

$\frac{\mathrm{d}y}{\mathrm{d} x}=2$

$2\left ( x-6\right )=\left ( y-7\right )$

2x-y=5

4 0

2 years ago