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PtichkaEL [24]
2 years ago
5

MATH: Composition of two functions...help needed with this problem

Mathematics
1 answer:
Evgesh-ka [11]2 years ago
3 0

The equation of Q(n) is Q(n) = \frac89 * (88n + 23)

<h3>How to determine the formula of Q(n)?</h3>

The functions are given as:

R(d) = \frac89 d

P(n) = 88n + 23

From the question, we understand that:

d = P(n)

This means that:

d = 88n + 23

Substitute d = 88n + 23 in R(d)

R(n) = \frac89 * (88n + 23)

Also, from the question

Q(n) = R(n)

So, we have:

Q(n) = \frac89 * (88n + 23)

Hence, the equation of Q(n) is Q(n) = \frac89 * (88n + 23)

Read more about composite functions at:

brainly.com/question/10687170

#SPJ1

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Step-by-step explanation:

n+1/2n=7/2

2n^2+1/2=7/2

4n^2+2=14

4n^2=12

n^2=3

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3 years ago
If their is a cube with 2/3ft what is the surface area?
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4 years ago
Which of the following are solutions to the equation below?
sladkih [1.3K]

Answer:

\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}

                  x=3,\:x=-\frac{1}{2}

Step-by-step explanation:

considering the equation

2x^2\:-\:4x\:-\:3\:=\:x

solving

2x^2\:-\:4x\:-\:3\:=\:x

2x^2-4x-3-x=x-x

2x^2-5x-3=0

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}

x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=2,\:b=-5,\:c=-3:\quad x_{1,\:2}=\frac{-\left(-5\right)\pm \sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}

solving

x=\frac{-\left(-5\right)+\sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}

x=\frac{5+\sqrt{\left(-5\right)^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}

x=\frac{5+\sqrt{49}}{2\cdot \:2}

x=\frac{5+7}{4}

x=3

also solving

x=\frac{-\left(-5\right)-\sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}

x=\frac{5-\sqrt{\left(-5\right)^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}

x=\frac{5-\sqrt{49}}{4}

x=-\frac{2}{4}

x=-\frac{1}{2}

Therefore,

                 \mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}

                  x=3,\:x=-\frac{1}{2}

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