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3 years ago

Please help! Correct answers only please!

Mathematics

1 answer:

bonufazy [111]3 years ago

3 0

Answer: (A) $2.2\text{ in}^3/\text{cookie}$ .

Step-by-step explanation:

From the given table , the dimension of the container for the 90cookies = 11 inch x 6 inch x 3 inch

Then, the volume of the container would be $11\times6\times3= 198 \ in^3$

Then, the ratio of cubic inches per cookie would be

$=\dfrac{\text{Volume of container}}{\text{Number of cookies in it}}\\\\=\dfrac{198}{90}\\\\=2.2\text{ in}^3/\text{cookie}$

So, the the ratio of cubic inches per cookie would be $2.2\text{ in}^3/\text{cookie}$ .

Hence, the correct option is (A) $2.2\text{ in}^3/\text{cookie}$ .

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I don't have an actual explanation because I simply guessed based on the dimensions and what made the most sense and I got it right. If someone has an explanation as to why it is 195 ft please lmk. Other than that, 195 ft is the correct answer.

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3 years ago

The sum of the number times 3 and 15

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3 years ago

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Yes, SAS.

Step-by-step explanation:

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3 years ago

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Using the t-distribution, as we have the standard deviation for the sample, it is found that there is a significant difference between the wait times for the two populations.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, we test if there is no difference, that is:

$H_0: \mu_A - \mu_B = 0$

At the alternative hypothesis, it is tested if there is difference, that is:

$H_1: \mu_A - \mu_B = 0$

<h3>What are the mean and the standard error of the distribution of differences?</h3>

For each sample, we have that:

$\mu_A = 73, s_A = \frac{2}{\sqrt{100}} = 0.2$

$\mu_B = 74, s_B = \frac{4}{\sqrt{100}} = 0.4$

For the distribution of differences, we have that:

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<h3>What is the test statistic?</h3>

It is given by:

$t = \frac{\overline{x} - \mu}{s}$

In which $\mu = 0$ is the value tested at the null hypothesis.

Hence:

$t = \frac{\overline{x} - \mu}{s}$

$t = \frac{-1 - 0}{0.447}$

$t = -2.24$

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Considering a one-tailed test, as stated in the exercise, with 100 - 1 = 99 df, using a t-distribution calculator, the p-value is of 0.014.

Since the p-value is less than the significance level of 0.05, it is found that there is a significant difference between the wait times for the two populations.

More can be learned about the t-distribution at brainly.com/question/16313918

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